A 3.7 cm -thick layer of oil is sandwiched between a 1.2 cm -thick sheet of glass and a 2.7 cm -thick sheet of polystyrene plastic.How long (in ns) does it take light incident perpendicular to the glass to pass through this 7.6 cm -thick sandwich?
The speed of light in a vacuum is approximately 3 x 10^8 m/s. However, the speed of light in a medium, such as glass or oil, is slower than in a vacuum and is characterized by the refractive index of the medium.
We can use Snell's Law to calculate the angle of refraction of the light as it passes through each layer, and then use the thickness and refractive index of each layer to calculate the time taken for the light to pass through the sandwich.
Let's start by calculating the refractive index of each layer. The refractive index of glass is approximately 1.5, and the refractive index of polystyrene is approximately 1.6. The refractive index of oil varies depending on the type of oil, but for this problem, we will assume it is approximately 1.45.
Next, we can use Snell's Law to calculate the angle of refraction of the light as it passes through each layer. Snell's Law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two media. Since the angle of incidence is 0° (the light is incident perpendicular to the glass), the angle of refraction is also 0° for the glass-oil interface and the oil-polystyrene interface.
Therefore, the light passes straight through the glass layer, and the only time delay comes from the oil and polystyrene layers. The time delay is given by:
time delay = thickness / (speed of light in medium)
For the oil layer, the thickness is 3.7 cm and the speed of light in oil is:
speed of light in oil = speed of light in vacuum / refractive index of oil speed of light in oil = (3 x 10^8 m/s) / 1.45 speed of light in oil = 2.07 x 10^8 m/s
Therefore, the time delay for the oil layer is:
time delay for oil = 3.7 cm / (2.07 x 10^8 m/s) = 1.79 x 10^-8 s
For the polystyrene layer, the thickness is 2.7 cm and the speed of light in polystyrene is:
speed of light in polystyrene = speed of light in vacuum / refractive index of polystyrene speed of light in polystyrene = (3 x 10^8 m/s) / 1.6 speed of light in polystyrene = 1.875 x 10^8 m/s
Therefore, the time delay for the polystyrene layer is:
time delay for polystyrene = 2.7 cm / (1.875 x 10^8 m/s) = 1.44 x 10^-8 s
The total time delay is the sum of the time delays for the oil and polystyrene layers:
total time delay = time delay for oil + time delay for polystyrene total time delay = 1.79 x 10^-8 s + 1.44 x 10^-8 s total time delay = 3.23 x 10^-8 s
Therefore, the time taken for the light to pass through the 7.6 cm-thick sandwich is:
time taken = 3.23 x 10^-8 s + time taken for glass layer time taken = 3.23 x 10^-8 s + (1.2 cm / (3 x 10^8 m/s)) time taken = 3.23 x
A 3.7 cm -thick layer of oil is sandwiched between a 1.2 cm -thick sheet of...
A 4.6 cm -thick layer of oil is sandwiched between a 1.2 cm -thick sheet of glass and a 1.6 cm -thick sheet of polystyrene plastic. How long (in ns) does it take light incident perpendicular to the glass to pass through this 7.4 cm -thick sandwich?
A 5.1-cm-thick layer of oil (n=1.46) is sandwiched between a 1.5-cm-thick sheet of glass and a 2.5-cm-thick sheet of polystyrene plastic (n=1.59). How long (in ns) does it take light incident perpendicular to the glass to pass through this 9.1-cm-thick sandwich? Express your answer in nanoseconds.
A 5.1-cm-thick layer of oil (n=1.46) is sandwiched between a 1.5-cm-thick sheet of glass and a 2.5-cm-thick sheet of polystyrene plastic (n=1.59). Part A How long (in ns) does it take light incident perpendicular to the glass to pass through this 9.1-cm-thick sandwich? Express your answer in nanoseconds.
A 7.5 cm-thick layer of oil (n=1.46) is sandwiched between a 2.8 cm-thick sheet of glass and a 4.2 cm-thick sheet of polystyrene plastic (n=1.59). How long (in ns) does it take light incident 42 degrees to the normal vector to the glass to pass through this 14.5 cm-thick sandwich?.... i need to know how to figure this problem out with the 42 Degrees to the normal vector, you did the first part but forgot the 42 degrees to normal...
A 1.8 cm thick layer of oil (n = 1.46) floats on top of 33 cm deep water (n = 1.33) in a rectangular bucket. When a laser beam is held at « = 37 degrees with respect to the surface of the water, its beam enters at the edge of the bucket and strikes the base of the bucket at its center. oil w a. Re-create the figure on your page and draw the path of the light as...
Problem: A 1.8 cm thick layer of oil (n = 1.46) floats on top of 33 cm deep water (n = 1.33) in a rectangular bucket. When a laser beam is held at $ = 37 degrees with respect to the surface of the water, its beam enters at the edge of the bucket and strikes the base of the bucket at its center. oil w a. Re-create the figure on your page and draw the path of the light...
Problem: A 1.8 cm thick layer of oil (n = 1.46) floats on top of 33 cm deep water (n = 1.33) in a rectangular bucket. When a laser beam is held at $ = 37 degrees with respect to the surface of the water, its beam enters at the edge of the bucket and strikes the base of the bucket at its center. oil w a. Re-create the figure on your page and draw the path of the light...
A 1-cm-thick layer of water stands on a horizontal slab of glass. A light ray in the air is incident on the water 62 degrees from the normal. After entering the glass, what is the ray's angle from the normal?
A ray of light is incident normally on a glass plate 6.00 cm thick and of refractive index n = 1.29 If the plate is turned through an angle of 74.0° about an axis perpendicular to the ray, what is the increase in the distance the ray travels in the glass? (nair = 1.00)
A ray of light traveling through air encounters a 1.8 cm -thick sheet of glass at a 37 ∘ angle of incidence. Assume n = 1.5. How far does the light ray travel inside the glass before emerging on the far side?