Let Z be a standard normal random variable. Determine the value z such that P(Z > z) =
a0.1003.
b -1.04
c-0.65
d 0.75
c 1.28
Solution :
Given that,
Using standard normal table ,
P(Z > z) = 0.1003
1 - P(Z < z) = 0.1003
P(Z < z) = 1 - 0.1003
P(Z < 1.28) = 0.8997
z = 1.28
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