Question

How to I solve this using modulo?

Problem 1: Develop a C program that reads a file of integers called “numbers.txt” It then prints the occurrence count of each digit from [0-9]. Your code must utilize the following function:

void freqFun (int num, int counters[])

In this prototype, num represents the number read from the file and counters represents the set of counters that hold the occurrence frequency of each digit. Digits that do not occur in the file shall be omitted in the screen printout.

Sample execution
numbers.txt: 123 457 102 345 0
Output
Number Frequency
0 : 2
1 : 2
2 : 2
3 : 2
4 : 1
5 : 1
7 : 1Problem 1: Develop a C program that reads a file of integers called “numbers.txt” It then prints the occurrence count of each digit from [0-9]. Your code must utilize the following function:
void freqFun (int num, int counters[])

In this prototype, num represents the number read from the file and counters represents the set of counters that hold the occurrence frequency of each digit. Digits that do not occur in the file shall be omitted in the screen printout.
Sample execution

numbers.txt: 123 457 102 345 0

Output:

Number Frequency
0 : 2
1 : 2
2 : 2
3 : 2
4 : 1
5 : 1
7 : 1

Answer 1

Answer:

File: Frequency.c

#include <stdio.h>
#include <stdlib.h>
int main()
{
   FILE *filePointer;//declare file pointer
   char ch;
   int arr[]={0,0,0,0,0,0,0,0,0,0},i;//Initialize Array for counter
   filePointer = fopen("numbers.txt", "r");//Opening file
   if (filePointer == NULL)//if file not open
   {
       printf("File is not available \n");
   }
   else//if file open successfull.
   {
       while ((ch = fgetc(filePointer)) != EOF)//until reach to end of file
       {
           switch(ch)//using switch increase the frequency counter
           {
               case '0': arr[0]=arr[0]+1;break;                      
               case '1': arr[1]=arr[1]+1;break;
               case '2': arr[2]=arr[2]+1;break;
               case '3': arr[3]=arr[3]+1;break;
               case '4': arr[4]=arr[4]+1;break;
               case '5': arr[5]=arr[5]+1;break;
               case '6': arr[6]=arr[6]+1;break;
               case '7': arr[7]=arr[7]+1;break;
               case '8': arr[8]=arr[8]+1;break;
               case '9': arr[9]=arr[9]+1;break;
               default:break;
           }
       }
       for(i=0;i<10;i++)//to display each digit frequency
       {
           if(arr[i]!=0)//display only if have counter more than zero
               printf("\n%d : %d",i, arr[i]);
       }
   }
   fclose(filePointer);//closing file pointer
   return 0;
}

Screen: