The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C7H5N3O6 (227.1 g/mol), is soluble in benzene C6H6. How many grams...
The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C7H5N3O6 (227.1 g/mol), is soluble in benzene C6H6. How many grams of TNT are needed to generate an osmotic pressure of 8.44 atm when dissolved in 189 ml of a benzene solution at 298 K. grams TNT
Homework Answers
P = 8.44atm
T = 298K
V = 189ml = 0.189L
PV = nRT
n = PV/RT
=8.44*0.189/(0.0821*298)
= 0.065moles
mass of C7H5N3O6 = no of moles * gram molar mass
= 0.065*227.1 = 14.76g >>>>answer
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