ZuoTi.Pro
Question

Consider a system with an activation energy of 50.0 kJ mol-1. Use the Arrhenius equation to...

Consider a system with an activation energy of 50.0 kJ mol-1. Use the Arrhenius equation to determine by what factor the rate constant of the reaction will change when the temperature is doubled, from 200 K to 400 K, all other factors being equal. (In other words, if you double the temperature, what happens to the rate constant k?)

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

thank you vmuch....

0 0
Add a comment
Know the answer?
Add Answer to:
Consider a system with an activation energy of 50.0 kJ mol-1. Use the Arrhenius equation to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic...

    To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation energy, and the reaction goes faster. This relationship is shown by the Arrhenius equation k=Ae−Ea/RT where k is the rate constant, A is the frequency factor, Ea is the activation energy, R = 8.3145 J/(K⋅mol) is the gas constant, and T is the...

  • 1) Calculate the activation energy in kJ/mol for the following reaction if the rate constant for...

    1) Calculate the activation energy in kJ/mol for the following reaction if the rate constant for the reaction increases from 93.5 M-1s-1 at 497.7 K to 1349.3 M-1s-1 at 636.7 K. do not include units, but make sure your answer is in kJ/mol! 2) A chemist constructs a plot of ln k vs. 1/T for a chemical reaction. The slope of the trendline for the data is -746 K. What is the activation energy for this reaction in kJ/mol? R...

  • A catalyst lowers the activation energy for a particular reaction from 75.0 kJ mol−1to 40.0 kJ...

    A catalyst lowers the activation energy for a particular reaction from 75.0 kJ mol−1to 40.0 kJ mol−1. By what factor does the rate constant increase if the catalyst is used at 25.0 °C? Assume that all rate constants obey the Arrhenius equation and that the pre-exponential factors for the uncatalyzed and catalyzed reactions are equal

  • To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic...

    To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation energy, and the reaction goes faster. This relationship is shown by the Arrhenius equation k=Ae−Ea/RT where k is the rate constant, A is the frequency factor, Ea is the activation energy, R = 8.3145 J/(K⋅mol) is the gas constant, and T is the...

  • Learning Goal: To use the Arrhenius equation to calculate the activation energy. As temperature rises, the...

    Learning Goal: To use the Arrhenius equation to calculate the activation energy. As temperature rises, the average kinetic energy of molecules increases. In a chemical reaction, this means that a higher percentage of the molecules possess the required activation energy, and the reaction goes faster. This relationship is shown by the Arrhenius equation k=Ae−Ea/RT where k is the rate constant, A is the frequency factor, Ea is the activation energy, R = 8.3145 J/(K⋅mol) is the gas constant, and T...

  • The activation energy for a reaction is 15 kJ mol-1 at 27° C. A catalyst lowers...

    The activation energy for a reaction is 15 kJ mol-1 at 27° C. A catalyst lowers the activation energy to 10 kJ mol at the same temperature. By what factor is the reaction rate increased? Assume that the reactant concentrations and the pre-exponential factor in the Arrhenius equation are unchanged. O A. 1.5 OB. 1.1 OC. 0.67 O D.7.4 O E. 1.7 x 107 Reset Selection

  • There are several factors that affect the rate of a reaction. These factors include temperature, activation...

    There are several factors that affect the rate of a reaction. These factors include temperature, activation energy, steric factors (orientation), and also collision frequency, which changes with concentration and phase. All the factors that affect reaction rate can be summarized in an equation called the Arrhenius equation: k=Ae−Ea/RT, where k is the rate constant, A is the frequency factor, Ea is the activation energy, R=8.314 J mol−1 K−1 is the gas constant, and T is the absolute temperature. A certain...

  • There are several factors that affect the rate of a reaction. These factors include temperature, activation...

    There are several factors that affect the rate of a reaction. These factors include temperature, activation energy, steric factors (orientation), and also collision frequency, which changes with concentration and phase. All the factors that affect reaction rate can be summarized in an equation called the Arrhenius equation: k=Ae−Ea/RT, where k is the rate constant, A is the frequency factor, Ea is the activation energy, R=8.314 J mol−1 K−1 is the gas constant, and T is the absolute temperature. A certain...

  • + The Arrhenius Equation: Graphical Method 9 of 11 Review Constants Periodic Table There are several...

    + The Arrhenius Equation: Graphical Method 9 of 11 Review Constants Periodic Table There are several factors that affect the rate constant of a reaction. These factors include temperature, activation energy steric factors (orientation), and also collision frequency, which changes with concentration and phase All the factors that affect the rate constant can be summarized in an equation called the Arthenius equation Part A k=A-E/RT where k is the rate constant. A is the frequency factor, Eis the activation energy...

  • 8) A reaction is found to have an activation energy of 38.0 kJ/mol. If the rate...

    8) A reaction is found to have an activation energy of 38.0 kJ/mol. If the rate constant for this reaction is 1.60 x 102 M-1-1 at 249 K, what is the rate constant at 436 K? 9) If the activation energy for a given compound is found to be 42.0 kJ/mol, with a frequency factor of 8.0 x 1010 s-1, what is the rate constant for this reaction at 298 K? 10) If the activation energy for a given compound...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT