To construct a 99% confidence interval where o is known, the correct critical value is 1.96....
To construct a 99% confidence interval where o is known, the correct critical value is 1.96.
True or false
Homework Answers
False
As the sigma is known we use z test The critical value at 99% is 2.58
Given CI level is 99%, hence α = 1 - 0.99 = 0.01
α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58
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To construct a 99% confidence interval where o is known, the
correct critical value is 1.96....
The confidence level is 99%, o is not known, and the histogram of 58 player salaries
Assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) find the critical value tα/2. (b) find the critical value zα/2, or (c) state that neither the normal distribution nor the t distribution applies. The confidence level is 99%, o is not known, and the histogram of 58 player salaries (in thousands of dollars) of football players on a team is as shown. Select the correct choice below and, if necessary, fill in the answer...
9.1.15 Construct a 99% confidence interval of the population proportion using the given information. x =...
9.1.15 Construct a 99% confidence interval of the population proportion using the given information. x = 125, n = 250 Click here to view the table of critical values. The lower bound is The upper bound is (Round to three decimal places as needed.) Table of critical values -X Area in Each Tail, i Critical Value, Level of Confidence, (1 - a). 100% 90% 95% 99% 0.05 0.025 0.005 1645 1.96 2.575 Print Done Enter your answer in the edit...
X 9.1.15 Construct a 99% confidence interval of the population proportion using the given information. X...
X 9.1.15 Construct a 99% confidence interval of the population proportion using the given information. X = 125, n = 250 Click here to view the table of critical values. The lower bound is a The upper bound is (Round to three decimal places as needed.) - X Table of critical values Area in Each Toil, Critical Value 4,4 L645 Level of Confidence, (1 - a). 100% 90% 95% 99% 0.05 0.025 0.005 1.96 2.575 Print Done ou al
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the...
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Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the...
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A 99% confidence interval for is given by: The multiplier is __________ . A. 2.576 B. 1.96...
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Find the critical value t* for the following situations. a) a 99% confidence interval based on...
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ol. Find the critical value a/2 needed to construct a confidence interval of the given level...
ol. Find the critical value a/2 needed to construct a confidence interval of the given level with the given sample size. Round the answers to three decimal places. Part 1 of 4 (a) For level 98% and sample size 8 Critical value = х Part 2 of 4 (b) For level 99% and sample size 13 Critical value = Part 3 of 4 (c) For level 99.5% and sample size 28 Critical value = Part 4 of 4 (d) For...
9.1.15 Construct a 99% confidence interval of the population proportion using the given information. x = 125, n = 250 Click here to view the table of critical values. The lower bound is The upper bound is (Round to three decimal places as needed.) Table of critical values -X Area in Each Tail, i Critical Value, Level of Confidence, (1 - a). 100% 90% 95% 99% 0.05 0.025 0.005 1645 1.96 2.575 Print Done Enter your answer in the edit...
X 9.1.15 Construct a 99% confidence interval of the population proportion using the given information. X = 125, n = 250 Click here to view the table of critical values. The lower bound is a The upper bound is (Round to three decimal places as needed.) - X Table of critical values Area in Each Toil, Critical Value 4,4 L645 Level of Confidence, (1 - a). 100% 90% 95% 99% 0.05 0.025 0.005 1.96 2.575 Print Done ou al
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.9 8.4 7.2 4.3 6.8 2.7 7.2 4.8...
Use the standard normal distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.21. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 3.2 6.8 6.1 3.6 6.3 7.1 6.4 5.5...
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