In an L-R-C series circuit, the source has a voltage amplitude of 124 V , R = 80.0 Ω , and the reactance of the capacitor is 475 Ω . The voltage amplitude across the capacitor is 355 V .
In an L-R-C series circuit, the source has a voltage amplitude of 124 V , R...
In a series R-L-C circuit the voltage amplitude across the resistor is 35.0 V, across the capacitor is 95.0 V and across the inductor is 55.0 V. When the source sinusoidal frequency is 10.6 KHz and the resistor value is 60.0 ohms A. What is the capacitance of the capacitor?
A series L-R-C circuit is driven with AC voltage of amplitude Vin and frequency ω. Define Vout to be the amplitude of the voltage across the capacitor. The resistance of the resistor is R, the capacitance of the capacitor is C, and the inductance of the inductor is L.(Figure 1) What is the ratio VoutVin? Express your answer in terms of either R, ω, L, and C or R, XL =ωL, and XC =1ωC. Vin c+ Vout
In a series circuit, suppose R=120Ω, L=220mH, C=0.60μF, V=75V, and ω=5550rad/s. Find the current amplitude I. Find the voltage amplitude across the resistor. Find the voltage amplitude across the inductor. Find the voltage amplitude across the capacitor.
can you explain how to answer this question In an R-L-C ac series circuit the voltage across the capacitor is 64 V and the voltage amplitude across the inductor is 96 V. Does the source voltage lag or lead the current in the circuit? (a) lag (b) lead
In a series R-L-C circuit, R = 380 Ω , L = 0.330 H and C = 1.10×10−2μF . Part A What is the resonance angular frequency of the circuit? Part B The capacitor can withstand a peak voltage of 550 V . If the voltage source operates at the resonance frequency, what maximum voltage amplitude can it have if the maximum capacitor voltage is not exceeded?
In a series R-L-C circuit, L = 0.190 H , C = 84.5 μF and the voltage amplitude of the source is 290 V . Part A What is the resonance angular frequency of the circuit? ω0 = rad/s SubmitMy AnswersGive Up Part B When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.610 A . What is the resistance R of the resistor? R = Ω SubmitMy AnswersGive Up Part C At...
6) In an L-R-C series circuit L = 0.440 H, R 380.0 n, and C-5.70μF. The 6) voltage amplitude of the source is 250.0 V. Find the rms voltage across the capacitor when the source operates at resonance
Exercise 31.29 In an L-R-C series circuit, 310 ,0.396 H and 5.98x10-8F. When the ac source operates at the resonance frequency of the circuit, the current amplitude is 0.505 A. Part A What is the voltage amplitude of the source ? ANSWER: V V Part B What is the amplitude of the voltage across the resistor? ANSWER: V Part 6 What is the amplitude of the voltage across the inductor? ANSWER: Vi V Part D What is the amplitude of...
A series R-L-C circuit is connected to a 110 Hz ac source that has Vrms = 80.0 V . The circuit has a resistance of 65.0 Ω and an impedance of 104 Ω at this frequency. What average power is delivered to the circuit by the source?
In a series R-L-C circuit, L = 0.215 H , C = 82.5 μF and the voltage amplitude of the source is 260 V . 1)What is the resonance angular frequency of the circuit? 2)When the source operates at the resonance angular frequency, the current amplitude in the circuit is 0.595 A . What is the resistance R of the resistor? 3)At the resonance frequency, what are the peak voltages across the inductor, the capacitor, and the resistor?