At 90% confidence, how large a sample should be taken to obtain a margin of 0.016 error of for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p * . Round up to the next whole number.
When prior estimate for proportion is not specified then p = 0.50
Sample size = Z2/2 * p( 1 - p) /
E2
= 1.64492 * 0.50 * 0.50 / 0.0162
= 2642.28
n = 2643 (Rounded up to nearest integer)
At 90% confidence, how large a sample should be taken to obtain a margin of 0.016...
At 90% confidence, how large a sample should be taken to obtain a margin of error of 0.011 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p. Round up to the next whole number
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.039 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p*. Round up to the next whole number.
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.017 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p *. Round up to the next whole number.
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How large a sample should be selected to provide a 95% confidence interval with a margin of error of 10? Assume that the population standard deviation is 40. Round your answer to next whole number.
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