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At 90% confidence, how large a sample should be taken to obtain a margin of 0.016...

At 90% confidence, how large a sample should be taken to obtain a margin of 0.016 error of for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p * . Round up to the next whole number.

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Answer #1

When prior estimate for proportion is not specified then p = 0.50

Sample size = Z2/2 * p( 1 - p) / E2

= 1.64492 * 0.50 * 0.50 / 0.0162

= 2642.28

n = 2643 (Rounded up to nearest integer)

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