3. There are an infinite number of possible normal distributions and we use the formula z...
3. There are an infinite number of possible normal distributions and we use the formula z = (x - m)/ s where m = mean and s = standard deviation, to convert values from any normal distribution to the standard normal distribution. We then calculate the answer in terms of the standard normal distribution and say that the answer we got is also the answer for the normal distribution we were working with. Why are we allowed to do that? (i.e why are we allowed to say that our answer that holds for the standard normal distribution also holds for any normal distribution?). (Hint; think about the formula for z).
Homework Answers
WE have z = (x - m)/ s which is the z score , it allows you to compare observations and calculate probabilities of normal populations. By calculating the z score and then make use of the standard normal table which is readily available to arrive at our results . This standard scale z score enablesus to compare observations that would otherwise be difficult. We can then make conclusion about the whole normal population since the normal distribution is X=Zs+m.
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3. There are an infinite number of possible normal distributions
and we use the formula z...
(i) The formula to convert any normal distribution to the standard normal distribution is z =...
(i) The formula to convert any normal distribution to the standard normal distribution is z = (X - µ)/ (ii) The standardized value measures distance from the mean in units of standard deviation. (iii) The area under a normal curve to the right of a z-score of zero is a proportion of 0.50. Select one: a. (i) and (iii) are correct statements but not (ii). b. (i) is a correct statement but not (ii) or (iii). c. (i) and (ii)...
We can now use the Standard Normal Distribution Table to find the probability P(-0.25 sz s...
We can now use the Standard Normal Distribution Table to find the probability P(-0.25 sz s 1). 0.05 0.06 0.07 0.08 0.09 -0.2 0.4013 0.3974 0.3936 0.3897 0.3859 0.00 0.01 0.02 0.03 0.04 Using these 1.0 0.8413 0.8438 0.8461 0.8485 0.8531 The table entry for z = -0.25 is 0.00 and the table entry for z = 1 is values to calculate the probability gives the following result. PC-0.25 sz s 1) P(Z < 1) - P(Z 5 -0.25) 10....
O RANDOM VARIABLES AND DISTRIBUTIONS Standard normal values: Advanced Let Z be a standard normal random...
O RANDOM VARIABLES AND DISTRIBUTIONS Standard normal values: Advanced Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c. P(0.6<Z<c)-0.2573 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places. 1× 5 ? Explanation Check PROBABILITY The curious die A peculiar die has the following properties: on any roll the probability of rolling either a 2, a 5, or a lis just...
Given X, and x, distributions that are normal or approximately normal with unknown o, and on,...
Given X, and x, distributions that are normal or approximately normal with unknown o, and on, the value of t corresponding to X, - X, has a distribution that is approximated by a Student's t distribution. We use the convention that the degrees of freedom is approximately the smaller of n - 1 and n, - 1. However, a more accurate estimate for the appropriate degrees of freedom is given by Satterthwaite's formula: 2 2 xn2 522 +$22) d.f. z...
Computer lecture on going from area to score with normal distribution - Saved to this PC t References Mailings Review View Help Tell me what you want to do In our last computer assignment we leam...
Computer lecture on going from area to score with normal distribution - Saved to this PC t References Mailings Review View Help Tell me what you want to do In our last computer assignment we leamed how to find the standard normal distribution up to the given score value a, that is we found P[Z <a). We used Excel instead of the standard nornal distribution table and evaluated P(Z<-1.72) with the command NORMDIST(1.T2B1,B2,TRUE) and we obtained 0.042716 approximately. Here Z...
Answer the number 3 and 4 question Worksheet 2: Chapters 3 and 8 (Normal Distributions; Sampling)...
Answer the number 3 and 4 question
Worksheet 2: Chapters 3 and 8 (Normal Distributions; Sampling) Math 243, Sunmmer '19, Vargas (c) (3.5) What percentage of all MLB players are shorter than your team's shortest player, according to the Normal distribution? What about taller than your team's tallest player? 3. (3.4) Consider the N(73.7,2.3) distribution for the height in the population of all MLB players. (a) From the population, find the intervals of player heights within one standard deviation of...
can you answer all three There are a few z scores that we use often that...
can
you answer all three
There are a few z scores that we use often that are worth remembering. The upper 50%, and 97.5 percent of a normal distribution are cut off by z scores of O a. 0.0, and 1.96 Ob. 1.0, and 1.64 C. plus and minus 1.96 d..50, and .975 QUESTION 11 If we have data that have been sampled from a population that is normally distributed with a mean of 50 and a standard deviation of...
We know the population standard deviation is $3,339," said Spencer. “So the next part of our...
We know the population standard deviation is $3,339," said Spencer. “So the next part of our analysis will be to calculate a z-test. The answer will help us determine if the average private university tuition and fee costs for our top 10 choices, which are $32,350, are significantly more expensive than the average claimed by the writer of the article.” To determine if the average private university tuition and fee costs are more expensive than the claimed average of $29,056,...
d. What is the average and standard deviation of these five z-scores? 3. A stress researcher...
d. What is the average and standard deviation of these five z-scores? 3. A stress researcher is measuring how fast people hit a red button after a loud noise. He gathers data from 81 people (N -81). His participants' reaction times are normally distributed. The average reaction time was 2.0 seconds, with a standard deviation of 0.2 seconds. Using a standard normal table (Table A-1), answer the following questions (hint: you need to convert raw scores into z-scores). a. What...
13. If we have a normal distribution with a mean of 75 and a standard deviation of 3. a. what z-score(s) would cut off the middle 40% of the distribution? b. what raw score(s) would cut off the l...
13. If we have a normal distribution with a mean of 75 and a standard deviation of 3. a. what z-score(s) would cut off the middle 40% of the distribution? b. what raw score(s) would cut off the lower 12% of the distribution? c, what raw score(s) would cut off the most extreme 5% of the distribution? d, what T-score(s) would cut off the upper 20% of the distribution?
13. If we have a normal distribution with a mean of...
We can now use the Standard Normal Distribution Table to find the probability P(-0.25 sz s 1). 0.05 0.06 0.07 0.08 0.09 -0.2 0.4013 0.3974 0.3936 0.3897 0.3859 0.00 0.01 0.02 0.03 0.04 Using these 1.0 0.8413 0.8438 0.8461 0.8485 0.8531 The table entry for z = -0.25 is 0.00 and the table entry for z = 1 is values to calculate the probability gives the following result. PC-0.25 sz s 1) P(Z < 1) - P(Z 5 -0.25) 10....
O RANDOM VARIABLES AND DISTRIBUTIONS Standard normal values: Advanced Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of c. P(0.6<Z<c)-0.2573 Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places. 1× 5 ? Explanation Check PROBABILITY The curious die A peculiar die has the following properties: on any roll the probability of rolling either a 2, a 5, or a lis just...
Given X, and x, distributions that are normal or approximately normal with unknown o, and on, the value of t corresponding to X, - X, has a distribution that is approximated by a Student's t distribution. We use the convention that the degrees of freedom is approximately the smaller of n - 1 and n, - 1. However, a more accurate estimate for the appropriate degrees of freedom is given by Satterthwaite's formula: 2 2 xn2 522 +$22) d.f. z...
Computer lecture on going from area to score with normal distribution - Saved to this PC t References Mailings Review View Help Tell me what you want to do In our last computer assignment we leamed how to find the standard normal distribution up to the given score value a, that is we found P[Z <a). We used Excel instead of the standard nornal distribution table and evaluated P(Z<-1.72) with the command NORMDIST(1.T2B1,B2,TRUE) and we obtained 0.042716 approximately. Here Z...
Answer the number 3 and 4 question
Worksheet 2: Chapters 3 and 8 (Normal Distributions; Sampling) Math 243, Sunmmer '19, Vargas (c) (3.5) What percentage of all MLB players are shorter than your team's shortest player, according to the Normal distribution? What about taller than your team's tallest player? 3. (3.4) Consider the N(73.7,2.3) distribution for the height in the population of all MLB players. (a) From the population, find the intervals of player heights within one standard deviation of...
can
you answer all three
There are a few z scores that we use often that are worth remembering. The upper 50%, and 97.5 percent of a normal distribution are cut off by z scores of O a. 0.0, and 1.96 Ob. 1.0, and 1.64 C. plus and minus 1.96 d..50, and .975 QUESTION 11 If we have data that have been sampled from a population that is normally distributed with a mean of 50 and a standard deviation of...
d. What is the average and standard deviation of these five z-scores? 3. A stress researcher is measuring how fast people hit a red button after a loud noise. He gathers data from 81 people (N -81). His participants' reaction times are normally distributed. The average reaction time was 2.0 seconds, with a standard deviation of 0.2 seconds. Using a standard normal table (Table A-1), answer the following questions (hint: you need to convert raw scores into z-scores). a. What...
13. If we have a normal distribution with a mean of 75 and a standard deviation of 3. a. what z-score(s) would cut off the middle 40% of the distribution? b. what raw score(s) would cut off the lower 12% of the distribution? c, what raw score(s) would cut off the most extreme 5% of the distribution? d, what T-score(s) would cut off the upper 20% of the distribution?
13. If we have a normal distribution with a mean of...
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