Question

The amount of time a service technician needs to change the oil in a car is...

The amount of time a service technician needs to change the oil in a car is uniformly distributed between 10 and 23 minutes. Let X = the time needed to change the oil on a car. Write the distribution.

Find P (x > 20).

Find the 65th percentile.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution :

Given that,

a = 10

b = 23

a) P(x < c) = (c - a) / (b - a)

P(x < 20) = (20 - 10) / (23 - 10)

P(x < 20) = 0.7692

b) 65 th PERCENTILE

= a + (b - a)p

= 10 + (23 - 10)0.65

= 18.45 minutes

Add a comment
Know the answer?
Add Answer to:
The amount of time a service technician needs to change the oil in a car is...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • If x, the time (in minutes) to complete an oil change job at certain auto service...

    If x, the time (in minutes) to complete an oil change job at certain auto service station, is uniformly distributed over the interval 20 to 30, inclusively (20 ≤ x ≤ 30), then the standard deviation of this distribution is

  • 8. Assume that the length of time needed to change the oil in a car at...

    8. Assume that the length of time needed to change the oil in a car at Fiona's Service Station is normally distributed with mean u = 15 minutes, and a standard deviation o = 5 minutes. If Fiona decides to offer a discount to those customers whose cars take the longest 20% of servicing time, what is the cutoff for the time required to receive the discount? EXCEL COMMAND

  • (1 point) It is known that the amount of time needed to change the oil in...

    (1 point) It is known that the amount of time needed to change the oil in a car is normally distributed with a standard deviation of 3 minutes. A random sample of 115 oil changes yielded a sample mean of 27 minutes. Compute the 92% confidence interval estimate for the population mean. Note: For each confldence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the contfidence limits. Confdence Interval-

  • The time required for an automotive center to complete the service oil change service on an automobile approximately follows a normal distribution

    1.The time required for an automotive center to complete the service oil change service on an automobile approximately follows a normal distribution, with a mean 19 minutes and a standard deviation of 3 minutes.  a. The automotive center guarantees customers that the service will take no longer than 20 minutes. If it does take ionger, the customer will receive the service for half-price. What percent of customers recelve the service for half-price? b. If the automotive center does not want to give the...

  • The shape of the distribution of the time required to get an oil change at a 20-minute oil change facility is unkno...

    The shape of the distribution of the time required to get an oil change at a 20-minute oil change facility is unknown. However, records indicate that the mean time is 21.5 minutes, and the standard deviation is 3.9 minutes. Complete parts (a) through (c). (a) To compute probabilities regarding the sample mean using the normal model, what size sample would be required? O A. Any sample size could be used. OB. The normal model cannot be used if the shape...

  • The shape of the distribution of the time required to get an oil change at a...

    The shape of the distribution of the time required to get an oil change at a 20-minute​ oil-change facility is unknown.​ However, records indicate that the mean time is 21.1 minutes and the standard deviation is 3.7 minutes ​(a) To compute probabilities regarding the sample mean using the normal​ model, what size sample would be​ required? A.Any sample size could be used. B.The sample size needs to be greater than or equal to 30. C.The sample size needs to be...

  • The time required for an oil change at a certain service station follows a distribution with...

    The time required for an oil change at a certain service station follows a distribution with mean 11.4 minutes and standard deviation 3.2 minutes. A random sample of 40 oil changes is selected. (a) Explain why the sampling distribution of ¯ x, the mean time of 40 oil changes, is approximately normally. (b) Find the mean and the standard deviation of the sampling distribution of ¯ x. Round your answers to one decimal place. (c) What is the probability that...

  • Question 1 1 pts The time it takes a service station to change the oil in...

    Question 1 1 pts The time it takes a service station to change the oil in a car is normally distributed with a mean of 20 minutes and a standard deviation of 5 minutes. What percentage of cars take longer than 30 minutes? Approximately 0% Approximately 2%. Approximately 14%. Approximately 100% Question 2 1 pts

  • The shape of the distribution of the time required to get an oil change at a...

    The shape of the distribution of the time required to get an oil change at a 10-minute oil-change facility is unknown. However, records indicate that the mean time is 11.2 minutes, and the standard deviation is 3.7 minutes. Complete parts (a) through (c). (a) To compute probabilities regarding the sample mean using the normal model, what size sample would be required? O A. The normal model cannot be used if the shape of the distribution is unknown. OB. Any sample...

  • The time it takes a mechanic to change the oil in a car is exponentially distributed...

    The time it takes a mechanic to change the oil in a car is exponentially distributed with a mean of 5 minutes. What is the probability that it will take a mechanic up to 6 minutes to change the oil?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT