Select all that apply. The molar solubility of AgCl in 6.5 × 10−3 M AgNO3 is 2.5 × 10−8 M. In deriving Ksp from these data, which of the following assumptions is (are) reasonable? Ksp is the same as solubility. The molar solubility of AgCl is the same in 6.5 × 10−8 M AgNO3 as in pure water. Solubility of AgCl is independent of the concentration of AgNO3. [Ag+] does not change significantly upon addition of AgCl to 6.5 × 10−3 M AgNO3. [Ag+] after the addition of AgCl to 6.5 × 10−3 M AgNO3 is the same as it would be in pure water.
Ksp is only a temperature dependent parameter. It will not depend upon the ionic strength.
AgCl dissociates into Ag+ & Cl- . But when the solution previously contains Ag+(from AgNO3) then due to common ion effect the dissociation of AgCl gets decreased.According to the expression of Ksp:
Ksp= [Ag+] [Cl-]
Here, major amount of Ag+ comes from strong electrolyte AgNO3 and very little comes from sparingly soluble salt AgCl. But Cl- comes from AgCl only.
Now, as previously mentioned that, Ksp is constant at a particular temperature, so the multiplied value of concentration of Ag+ & Cl- be constant. So, as Ag+ concentration becomes high, consequently Cl- concentration will be low and that's why the solubility of AgCl decreases and it depends upon the concentration of AgNO3.
So, it can be assumed that, Ag+ concentration rarely changes upon addition of AgCl where solution contain AgNO3 previously at very high concentration than the solubility of AgCl.
Select all that apply. The molar solubility of AgCl in 6.5 × 10−3 M AgNO3 is...
3. Calculate the molar solubility of AgCl in water. Calculate the molar solubility of AgCl a solution of 0.200M NaCl. Compare the molar solubility of AgCl in water and 0.200M in NaCl and explain the common ion effect. Ksp of AgCl is 1.77 x 10^-10
4) Calculate the molar solubility of AgCl (Ksp = 1.8 x 10-) at 25°C in: (a) Pure water (b) 3.0 M NH3 [Hint: AgCl(s) + 2NH3(aq) Ag(NH3)2(aq) + Cl(aq) K = 3.1 x 10
Calculate the solubility at 25°C of AgCl in pure water and in a 0.0080M AgNO3 solution. You'll find Ksp data in the ALEKS Data tab. Round both of your answers to 2 significant digits. The Ksp value of AgCl is 1.77 times 10 to the -10. Solubility in water: Solubility in 0.0080 AgNO3 solution:
5. a) Determine the molar solubility of PbSO4 in pure water, Ksp (PbSO4) = 1.82 * 10-8 b) A solution containing AgNO3 is mixed with a solution of NaCl to form a solution that is 0.10 M in AgNO3 and 0.075 M in NaCl. Calculate the value for the process. Will a precipitate of AgCl form? Give evidence to support your claim. Ksp (AgCl) = 1.77 10-10
What is the molar solubility of AgCl (Ksp = 1.80 × 10⁻¹⁰) in 0.980 M NH₃? (Kf of Ag(NH₃)₂⁺ is 1 × 10⁷)
What is the molar solubility of AgCl in 0.025 M CaCl2? For AgCl, Ksp = 1.6 x 10-10. You can assume that molar solubility, s, is very small. Select one: a. 1.6 x 10-11 M b. 3.2 x 10-9 M c. 8.5 x 10-12 M d. 2.5 x 10-10 M e. 6.2 x 10-13 M
TA What is the molar solubility of AgCl in 0.50 M NH3? Ksp for AgCl is 1.8x10-10 and K for Ag(NH3)2 + is 1.7x107 ANSWER: 1.3 x 10-5 M 2.0 x 10-2 M 5.5 x 10-2 M 5.8 x 10-2 M
What is the molar solubility of AgCl (Ksp = 1.80 x 10-10) in 0.330 M NH3? (Kf of Ag(NH3)2* is 1 x 107) IM What is the equilibrium constant for the solubility of FeCO3 (Ksp = 2.1 x 10-11) in NaCN? (Kf of Fe(CN)64-is 1.0 x 1035)
3. (5 pts) Calculate the molar solubility of AgCl in 0.1 M CaCl. Ksp for AgCl = 1.6 x 10" 188
14. What is the molar solubility of AgCl in pure water at 25°C? Ksp =1.8 x 10