Consider a glass of 160 mL of water at 27°C. Calculate the mass
of ice at -15°C that must be added to cool the water to 10°C after
thermal equilibrium is achieved. To find the mass of water use the
density of water = 1.0 g/mL.
_____ g
Let a gram ice is added, and let heat capacity of water = S j/g.°C
Change in temperature for water = 27 - 10 = 17
Mass of 160 ml water = 160 gram
Heat lost by water = 160S× 17 = 2720S
Change in temperature for ice
Consider a glass of 160 mL of water at 27°C. Calculate the mass of ice at...
A couple of small ice cubes at 0 °C are added to glass of warm water (mass = 0.255 kg, temperature = 65.9 °C) to cool it. All of the ice melts and the final temperature is measured to be 14.4 °C. What was the mass of the ice used?
A quantity of ice at 0 degree C is added to 50 g of water in a glass at 55 degree C. After the ice melted, the temperature of the water was 15 degree C. How much ice was added?
5. A 30-g ice cube is dropped into 160 g of water in a glass. If the water is initially at a temperature of 25 °C and the ice is at 0 °C, what is the final temperature of the drink? ANSWER: 8.5 °C
A. A 32.1 g of ice at 0 C is added to 120g of water in a 64.8 g aluminum cup. the cup and the water have an initial temperature of 23.7 C. Calculate the equilibrium temperature of the cup and its contents. B. Calculate the equilibrium temperature of the cup and its contents if the aluminum cup is replaced with one of equal mass made from glass.
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Ice of mass 52.0 g at -10.9° C is added to 220 g of water at 14.8° C in a 111 g glass container of specific heat 0.200 cal/g-°C at an initial temperature of 23.9° C. Find the final temperature of the system. °C
can someone tell me how they got this answer
0/1pts Question 7 Ice with a mass of 123,588 kg at-10.5°C is used to cool a beluga whale's water tank, which holds 1,017 m3 of water. If the water tank was initially at 19.0°C. to what final equilibrium temperature is the tank brought to? Answered margin of error +-2 % ect Answer 7.7535 Consider the following setup: Qice +Qmelt+ Qice-water +Qater = 0 Where Qice is the amount of thermal energy...
200 g of water at room temperature is poured into a 100 g glass jar also at room temperature. 150 g of ice cubes at −10◦C are added to the the water. (a) What is the temperature of the system when it reaches thermal equilibrium? (b) Describe in detail the contents of the jar once equilibrium is reached. Assume that the system is isolated and room temperature is 25◦C.
200 g of water at room temperature is poured into a 100 g glass jar also at room temperature. 150 g of ice cubes at −10◦C are added to the the water. (a) What is the temperature of the system when it reaches thermal equilibrium? (b) Describe in detail the contents of the jar once equilibrium is reached. **Assume that the system is isolated and room temperature is 25◦C.
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