A proton and a singly charged ion of mass 52 atomic mass units (amu) are accelerated through the same potential difference and enter a region of uniform magnetic field moving perpendicular to the magnetic field. What is the ratio of their kinetic energies? Tries 0/10 If the radius of the proton's circular path in the magnetic field is 13.2 cm , what is the radius of the path of the singly charged ion of 52 amu? Tries 0/10 By what factor must the magnetic field be multiplied by for the singly charge ion to have the same radius path as the proton?
A proton and a singly charged ion of mass 52 atomic mass units (amu) are accelerated...
A singly charged positive ion has a mass of 2.50*10^-26 kg. After being accelerated through a potential difference of 250V, the ion enters a magnetic field of 0.500 T, in a direction perpendicular to the field. Calculate the radius of the path of the ion in the field.
In a mass spectrometer, a singly charged ion having a particular velocity is selected by using a magnetic field of 7.0×10−2 T perpendicular to an electric field of 1.0×103 V/m . A magnetic field of this same magnitude is then used to deflect the ion, which moves in a circular path with a radius of 1.3 cm . What is the mass of the ion? Express your answer using two significant figures.
A singly charged ion of 7Li (an isotope of Lithium) has a mass of 1.16 x 10-26 kg. It is accelerated through a potential difference of 220 V and then enters a magnetic field with magnitude 0.723 T perpendicular to the path of the ion. What is the radius of the ion's path in the magnetic field?
2. A proton with charge gp 1.6 x 10 19C and mass M, is accelerated through a potential difference V. The proton then enters a region of con stant magnetic field B oriented perpendicular to its path. In this region, the proton's path is circular with radius Rp Another particle with the same charge as the proton but a different mass M, follows under the same conditions. Its radius R., is 1.4 times as large as Rp. what is the...
A proton is accelerated from rest through a potential differences of 1.0 kV. It enters a uniform magnetic field of 4.5 mT that is initially perpendicular to its velocity. (a) Find the radius of the proton's circular path (b). Calculate the period of revolution of the proton.
It is then deflected by a uniform magnetic field (perpendicular to the ion's velocity) into a semicircle of radius R. Now a triply charged ion of mass m' isaccelerated through the same potential difference and deflected by the same magnetic field into a semicircle of radius R' = 4R. What is the ratio of the masses of theions? m'/m =
Singly charged uranium-238 ions are accelerated through a potential difference of 3.10 kV and enter a uniform magnetic field of magnitude 1.38 T directed perpendicular to their velocities. (a) Determine the radius of their circular path. (Give your answer to three significant figures.) (b) Repeat this calculation for uranium-235 ions. (Give your answer to three significant figures.)
Chapter 28, Problem 079 A proton, a deuteron (q = +e, m = 2.0 u), and an alpha particle (q 2e, m 4.0 u) are accelerated through the same potential difference and then enter R the same region of uniform magnetic field ,moving perpendicular to . (a) What is the ratio of the proton's kinetic energy Ko to the alpha particle's kinetic energy K? (b) What is the ratio of deuteron's kinetic energy Kd to Ka? Assume that the radius...
A singly charged ion of unknown mass moves in a circle of radius 12.5 cm in a magnetic field of 9.0 T. The ion was accelerated through a potential difference of 7.0 kV before it entered the magnetic field. What is the mass of the ion? ___kg
0/1 points | Previous Answers SerCP10 19.P.037 A singly charged positive ion has a mass of 2.40 x 10-26 kg. After being accelerated through a potential difference of 258 V, the ion enters a magnetic field of 0.550 T, in a direction perpendicular to the field. Calculate the radius of the path of the ion in the field. My Notes Ask Your Teac 1,24 Your response differs from the correct answer by more than 10%. Double check your calculations. cm...