Calculate the standard reduction potential for the half-reaction
AgBr(s)+e−→Ag(s)+Br−(aq)
Express the potential to two decimal places.
It is the standard value and its value is fixed these are standard values and is 0.07V
Calculate the standard reduction potential for the half-reaction AgBr(s)+e−→Ag(s)+Br−(aq) Express the potential to two decimal places.
Consider the following information at 25 ºC: AgBr(s) + e- → Ag(s) + Br-(aq) Eº(AgBr(s),Ag(s)) = 0.07133 V Ag+(aq) + e- → Ag(s) Eº(Ag+(aq),Ag(s)) = 0.7996 V What is the value of the solubility product equilibrium constant Ksp(AgBr) of silver bromide? AgBr(s) ↔ Ag+(aq) + Br-(aq) Ksp(AgBr)
Question 22 (5 points) Given the following half reactions: - AgBr(s) + e- Ag+ (aq) + e- Ag(s) + Br- (aq) E° = 0.07V → Ag (s) E° = 0.80V - Calculate the Ksp for PbSO4 at 25 degrees C. Please enter your answer in scientific notation, such as 1.2E10 or 1.2E-10 and keep two significant figures.
Question 5 Calculate Eº cell for the reaction below, 2 AgBr(aq) + 2 Hg(1) 2 Ag(s) + Hg2Br2(5) given the following standard reduction potentials. Hg2Br2(s) + 2 - 2 Hg(1) + 2 Br"(aq) E = +0.140 V AgBr(aq) + e - Ag(s) + Br" (aq) E = +0.071 V O a. -0.211 V O b. +0.069 V O C. +1.97 v O d. -0.069 V O e. +0.211 V Question 6 Given the following substances and their vapor pressures at...
Given the following reactions, AgBr(s) = Ag+ (aq) + Br(aq) Ksp = 5.8 x 10-13 Ag+ (aq) + 2 CN"(aq) = Ag(CN)2(aq) Kf = 9.5 x 1021 determine the equilibrium constant for the reaction below. AgBr(s) + 2 CN"(aq) =Ag(CN)2(aq) + Br(aq) Answer: 1.2E21 Check
Consider the two reduction half-reactions: Br2(l) + 2 e− ⟶ 2 Br−(aq) Eo = 1.09 V Ag+(aq) + e− ⟶ Ag(s) Eo = 0.337 V Use the electrode potentials above to calculate Eocell and ∆Gorxn for the reaction below, and determine if it is the reaction for a voltaic cell or an electrolytic cell.
Given the following reactions, AgBr(s) Ag (aq) + Br(aq) Ag*(aq)2 CN (aq)=Ag(CN)2(aq) K 1.2E+21 determine the equilibrium constant for the reaction below AgBr(s)2 CN-(aq)= Ag(CN)2 (aq) Brr(aq) Ksp 5.4E-13
The standard reduction potential of the Ag Ag electrode is +0.80 V and the standard potential of the cell Fe(s) Fe3+(aq) || Ag" (aq) Ag(s) is +0.84 V. What is the standard reduction potential of the Fe3+1Fe electrode? +1.64 V +0.04 V O-1.64v -0.04 v -0.12 V Question 10 (1 point) In the following cell, A is a standard Co2+1Co electrode connected to a standard hydrogen electrode. If the voltmeter reading is -0.28 V, which half-reaction occurs in the left-hand...
Consider the following half-reactions: Half-reaction E° (V) Ag+(aq) +e → Ag(s) 0.799V Cu2+(aq) + 2e → Cu(s) 0.337V Mg2+(aq) + 2e —— Mg(s) -2.370V The strongest oxidizing agent is: enter symbol The weakest oxidizing agent is: The weakest reducing agent is: The strongest reducing agent is: Will Mg(s) oxidize Ag(s) to Ag+(aq)? V Which species can be oxidized by Cu2+(aq)? If none enter none. Consider the following half-reactions: Half-reaction E° (V) 2Br (aq) 1.080V Br2(1) + 2e — Ni2+(aq) +...
10. You want to know the standard reduction potential for the Cr* (aq)|Cr(s) half- reaction Cr3 + (aq) + 3e-→ Cr(s) y, your textbook only lists the following data for chromium: Cr3+ (aq) + e-→ Cr2+ (aq) Cr2+ (aq) + 2e-→ Cr(s) E' =-0.424 V E' =-0.900 V What is the standard reduction potential for the Cr (a)Cr(s) half-reaction at 25 °C? A)-0.741 V B)-1.324 V C) 0.382V D)-0.141 V E) 0.476 V
Item 10: Question (10 pts.) Given the following reactions, AgBr(s) = Ag+(aq) + Br-(aq) Kap = 5.4E-13 Ag+ (aq) + 2 CN-(aq) — Kp = 1.2E+21 Ag(CN), (aq) determine the equilibrium constant for the reaction below. AgBr(s) + 2 CN- (aq) = Ag(CN)2 (aq) + Br(aq) Submit Submit and Next O: Mark this question for later review. - Skip to Previous