Question

Im stuck on this matlab question An 80% solution, an 11% solution, and an 18% solution of nitric acid are to be mixed to get 150 mL of a 12% solution. If the volume of acid from the 8.0% solution equals half the volume of acid from the other two solutions, how much of each is needed? Set your equations and define the variables being used to find the volume of each solution.

Answer 1

The code will be

if x ml of first, y ml of second and z ml of third are mixed so the equations will be

x+y+z=150

0.08*x+0.11y+0.18z=0.12*150

x=(y+z)/2

So using matlab we can see that the code will be

A=[1 1 1;

0.08 0.11 0.18;

2 -1 -1];

B=[150;

150*0.12;

0];

X=A\B

And the solution is

x=50.0000
y=57.1429
z=42.8571

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