Question

a survey of 400 new managers revealed that only 39% of them had received management training. let p represent the true proportion of new managers who receive management training. we want to generate a 90% confidence interval for the true proportion of managers who have received management training using a simulation method. in order to do this, we will use (a. bootstrap, b. Randomization). here is how we do it: 1. sample (a. with replacement, b. without replacement) from the original (a. 400, b. 1000, c. 39, d. 90) observations. 2. computer and record the (a. bootstrap proportion, b. bootstrap mean, c. randomization proportion, d. randomization mean, e. true proportion, f. true mean) 3. repeat step 1-2 (a. 1000, b. 400, c. 39, d. 90) times 4. draw the distribution of (a. bootstrap statistics, b. randomization statistics, c. population proportions) 5. find the (a. endpoints of the middle 90% of the distribution, b. proportion of the distribution that is as extreme or more extreme than your observed value, c. proportion of the distribution that is as extreme or less extreme than your observed value, d. endpoints of the middle 95% of the distribution) which is your (a. confidence interval, b. z-value, c. t-value, d. p-value).

Answer 1

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