Question

In Legv8 assembly implement a swap procedure that swaps the values in two different 8-byte integers in memory.

Answer 1

The swap in high level program will look like this,

swap(int a, int b)

{

        int temp = a;

        a = b;

         b = temp;

}

This can be rewritten in legv8 assembly code as follows

LDURB X0, a    // Loading the value of 'a' in X0

LDURB X1, b   // Loading the value of 'b' in X1

STURB X1, a   // Storing the value of 'b' (ie, X1) to 'a'

STURB X0, b    // Storing the value of 'a' (ie, X0) to 'b'