A standard six sided dice is tossed repeatedly. Let N be the total number of observed 1s and 2s.
For independent individual outcomes, calculate p(N=infinity)
(Hint continuity)
Full solution with justification.
When a die is thrown n times
P(N = k) =
P(k-0.5 <= N <= k+0.5) {continuity correction }
N follow binomial distribution with n and p = 1/3
N follow normal distribution with mean =n/3 and sd =sqrt(n/3 * 1/3*2/3) =sqrt(2n/27)
hence
P(N = k) =
P((k-0.5 - n/3)/sqrt(2n/27) < Z < (k+0.5 -n/3)/sqrt(2n/27))
when n tend to infinity and k tend to infinity
(k-0.5 - n/3)/sqrt(2n/27) (k+0.5 - n/3)/sqrt(2n/27)
hence
P(N = k) = 0
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