Beginning with a 0.0245 M Cu2+ solution and ignoring ohmic and overpotentials, what will the potential be when 99.9% of the Cu2+ has been converted to Cu? Cu2+ + 2e- >Cu Eo= +0.342 volts
Answer: +0.206 volts
Beginning with a 0.0245 M Cu2+ solution and ignoring ohmic and overpotentials, what will the potential...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 oC. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V? Cu2+(ag) + Pb(s) → Cu(s) + Pb2+(ag) Hint: [Pb2+] + [Cu2+] = (1.5M + 0.05M) = 1.55 M total Hint: the standard potential of Pb2+ + 2e- → Pb(s) is -0.130 and the standard potential...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 oC. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What is the initial cell potential? Hint: the standard potential of Pb2+ + 2e- → Pb(s) is -0.130 and the standard potential of Cu2+ + 2e- → Cu(s) is +0.340. Hint #2: Use [Cu2+] as the product and [Pb2+] as the reactant. The equation we are supposed to use is E= Eo-...
For the following cell what is the cell potential under standard conditions? Zn + Cu2+ → Cu + Zn2+ If Cu2+ + 2e- → Cu E° = 0.34V and Zn2+ + 2e- → Zn E° = -0.76 V
Calculate the equilibrium potential of a copper wire immersed in 0.0009 M CuSO4 solution. The standard electrode potential for the reaction Cu2+ 2e -Cu at 25°C is 0.34 V (NHE). Now, answer the following questions and enter your results (numerical number only) Calculate the ionic strength (M) of the solution Submit Answer Tries 0/25 Calculate the activity coefficient of Cu2+. Submit Answer Tries 0/25 Calculate the equilibrium potential (v) of the copper wire electrode. Note: use activity instead of concentration...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V? Cu2+ (aq) + Pb(s) + Cu(s) + Pb2+ (aq) Hint: [Pb2+] + [Cu2+] = (1.5M + 0.05M) = 1.55 M total Hint: the standard potential of Pb2+ + 2e → Pb(s) is -0.130 and the...
A copper, Cu(s), electrode is immersed in a solution that is 1.00 M in ammonia, NH3, and 1.00 M in tetraamminecopper(I), [Cu(NH). If a standard hydrogen electrode is used as the cathode, the cell potential, Ecell, is found to be 0.074 V at 298 K Constants Periodic Table Use the standard reduction potentials shown here to answer the questions Reduction half-reaction E (V) Cu2+ (aq) 2e Cu(s) 0.337 2H + (aq) + 2e →H, (g) | 0.000 ▼ Part A...
*A copper, Cu(s), electrode is immersed in a solution that is
1.00 M in ammonia, NH3, and 1.00 M in tetraamminecopper(II),
[Cu(NH3)4]2+. If a standard hydrogen electrode is used as the
cathode, the cell potential, Ecell, is found to be 0.070 V at 298
K.
A copper, Cu(s), electrode is immersed in a solution that is 1.00 M in ammonia, NH3, and 1.00 M in tetraamminecopper(II), [NH. If a standard hydrogen electrode is used as the cathode, the cell potential,...
3. For the reaction below, what is the value of E when [Cu2+]-0.04 M and [Fe2+]=0.4 M? Cu(aq) + Fe(s)Cu(s) + Fe2 (aq) E +0.78 V 4. How many minutes are required to plate 2.08 g of Cu at a current of 1.26 A? Cu2 (aq) +2e Cu(s)
When the Cu2+ concentration is 5.57×10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.419V. What is the Mn2+ concentration? Cu2+(aq) + Mn(s) Cu(s) + Mn2+(aq) Answer: _____M
Instead of using zinc, a student accidentally used a 1 M solution of silver (Ag). Based on the information in the table below, what would be the theoretical cell voltage, Eocell, when it is used in a galvanic cell with copper? Electrode Eo Ag+ + e- à Ag +0.80 V Cu2+ + 2e- à Cu +0.34 V Pb2+ + 2e- à Pb -0.13 V Zn2+ + 2e- à Zn -0.76 V Al3+ + 3e- à Al -1.66 V