For the reaction in the previous problem, that is, 2HI(g) ↔ H2(g) + I2(g) Keq =...

Question

Question

For the reaction in the previous problem, that is, 2HI(g) ↔ H2(g) + I2(g) Keq =...

For the reaction in the previous problem, that is,

2HI(g) ↔ H₂(g) + I₂(g) K_eq = 0.016

Initially a container contains 0.39 M HI and no product. What is the equilibrium concentration of H₂?

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

please rate

Add a comment

Answer 2

Similar Homework Help Questions

For the reaction: 2HI(g) ↔ H2(g) + I2(g) Keq = 0.016 Initially a container contains 0.60...

For the reaction: 2HI(g) ↔ H2(g) + I2(g) Keq = 0.016 Initially a container contains 0.60 M HI, 0.038 M H2, and 0.15 M I2 at equilibrium. What is the new equilibrium concentration of H2, if the H2 concentration is increased by 0.276 M?
Given that the reaction H2 (g) + I2 (g) <--> 2HI (g) is at equilibrium and...

Given that the reaction H2 (g) + I2 (g) <--> 2HI (g) is at equilibrium and the measured concentrations of each component of the reaction are [H2] = 0.22 M, [I2] = 0.22 M, and [HI] = 1.56 M, write the equilibrium expression and then calculate Keq.
The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is...

The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is 794 at 25 °C. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇌ 1/2 H2 (g) + 1/2 I2 (g) 1588 0.0013 397 28 0.035

Given the equilibrium reaction: 2HI(g) H2(g) + I2(g) A sample mixture of HI, H2, and 12,...

Given the equilibrium reaction: 2HI(g) H2(g) + I2(g) A sample mixture of HI, H2, and 12, at equilibrium, was found to have [H2]- 1.4 x 102 Mand [HI 4.0 x 102 M. If Keq 1.0 x 10, calculate the molar concentration of I2 in the equilibrium mixture, Enter your answer in the provided box. ]= м
Consider the following chemical reaction: H2 (g) + I2 (g) 2HI (g) At equilibrium in a...

Consider the following chemical reaction: H2 (g) + I2 (g) 2HI (g) At equilibrium in a particular experiment, the concentrations of H2, I2, and HI were 0.02, 0.021 and 0.160 M respectively. The value of Keq for this reaction is __________.
The equilibrium constant for the reaction: H2(g) + I2(g) <--> 2HI(g) is 54 at 700 K....

The equilibrium constant for the reaction: H2(g) + I2(g) <--> 2HI(g) is 54 at 700 K. A mixture of H2, I2 and HI, each at 0.020 M, was introduced into a container at 700 K. Which of the following is true? At equilibrium, [H2] = [I2] = [HI]. No net change occurs because the system is at equilibrium. The reaction proceeds to the left producing more H2(g) and I2(g). The reaction proceeds to the right producing more HI(g). At equilibrium,...

A student ran the following reaction in the laboratory at 647 K: 2HI(g) H2(g) + I2(g)...

A student ran the following reaction in the laboratory at 647 K: 2HI(g) H2(g) + I2(g) When she introduced 0.395 moles of HI(g) into a 1.00 liter container, she found the equilibrium concentration of I2(g) to be 3.95×10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction.
At a certain temperature, the equilibrium constant, ?c, for this reaction is 53.3. H2(g)+I2(g)↽−−⇀2HI(g)?c=53.3 At this...

At a certain temperature, the equilibrium constant, ?c, for this reaction is 53.3. H2(g)+I2(g)↽−−⇀2HI(g)?c=53.3 At this temperature, 0.500 mol H2 and 0.500 mol I2 were placed in a 1.00 L container to react. What concentration of HI is present at equilibrium?
For the reaction H2 (g) + I2 (g) = 2HI (g); Kc =50.0. Calculate the concentration...

For the reaction H2 (g) + I2 (g) = 2HI (g); Kc =50.0. Calculate the concentration of HI (g) at equilibrium if the initial concentration of each substance is 0.0600 M and the reaction mixture is allowed to come to equilibrium. (Hint: ICE Table)

Consider this reaction: H 2 (g)+ I 2 (g)⇌2HI(g) H2(g)+I2(g)⇌2HI(g) A rxn mixture in a 3.73...

Consider this reaction: H 2 (g)+ I 2 (g)⇌2HI(g) H2(g)+I2(g)⇌2HI(g) A rxn mixture in a 3.73 L flask at a certain temperature initially contains 0.766 g H2 and 96.7 g I 2 I2 . At equilibrium, the flask holds 90.3 g HI . Calculate the equilibrium constant (Kc)(Kc) for the reaction at this temperature. Record your answer using two significant figures.

For the reaction in the previous problem, that is, 2HI(g) ↔ H2(g) + I2(g) Keq =...

Homework Answers

Add Answer to:
For the reaction in the previous problem, that is, 2HI(g) ↔ H2(g) + I2(g) Keq =...

Post as a guest

Earn Coins

For the reaction: 2HI(g) ↔ H2(g) + I2(g) Keq = 0.016 Initially a container contains 0.60...

Given that the reaction H2 (g) + I2 (g) <--> 2HI (g) is at equilibrium and...

The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is...

Given the equilibrium reaction: 2HI(g) H2(g) + I2(g) A sample mixture of HI, H2, and 12,...

Consider the following chemical reaction: H2 (g) + I2 (g) 2HI (g) At equilibrium in a...

The equilibrium constant for the reaction: H2(g) + I2(g) <--> 2HI(g) is 54 at 700 K....

A student ran the following reaction in the laboratory at 647 K: 2HI(g) H2(g) + I2(g)...

At a certain temperature, the equilibrium constant, ?c, for this reaction is 53.3. H2(g)+I2(g)↽−−⇀2HI(g)?c=53.3 At this...

For the reaction H2 (g) + I2 (g) = 2HI (g); Kc =50.0. Calculate the concentration...

Consider this reaction: H 2 (g)+ I 2 (g)⇌2HI(g) H2(g)+I2(g)⇌2HI(g) A rxn mixture in a 3.73...

For the reaction in the previous problem, that is, 2HI(g) ↔ H2(g) + I2(g) Keq =...

Homework Answers

Add Answer to: For the reaction in the previous problem, that is, 2HI(g) ↔ H2(g) + I2(g) Keq =...

Post as a guest

Earn Coins

Add Answer to:
For the reaction in the previous problem, that is, 2HI(g) ↔ H2(g) + I2(g) Keq =...