A real battery with internal resistance 0.550 Ω and emf 9.00 V is used to charge a 54.0-µF capacitor. A 15.0-Ω resistor is put in series with the battery and the capacitor when charging.
(a) What is the time constant for this circuit?
_______s
(b) What is the time when the capacitor has reached half its maximum charge?
_______s
(c) What is the current through the capacitor at this time?
_______A
A real battery with internal resistance 0.550 Ω and emf 9.00 V is used to charge...
A real battery is not just an emf. We can model a real 1.5 V battery as a 1.5 V emf in series with a resistor known as the "internal resistance", as shown in the figure(Figure 1) . A typical battery has 1.0 Ω internal resistance due to imperfections that limit current through the battery. When there's no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V,...
An uncharged capacitor and a resistor are connected in series to a source of emf. If = 9.00 V, C = 17.0 µF, and R = 100 , find the following:(a) the time constant of the circuit______ s(b) the maximum charge on the capacitor______ µC(c) the charge on the capacitor after one time constant_______ µC
A battery with EMF 90.0 V has internal resistance Rb = 8.43 Ω .What is the reading Vv of a voltmeter having total resistance Rv = 475 Ω when it is placed across the terminals of the battery?What is the maximum value that the ratio Rb/Rv may have if the percent error in the reading of the EMF of a battery is not to exceed 5.00 % ?
Calculate the terminal voltage for a battery with an internal resistance of 0.750 Ω and an emf of 6.50 V when the battery is connected in series with an 870-Ω resistor.
A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R1 = R3 = 24Ω, R4 = R5 = 112 Ω and R2 = 126 Ω. The measured voltage across the terminals of the batery is Vbattery = 11.73 V.2) What is r, the internal...
A battery with an emf of 12 V and an internal resistance of 1Ω is used to charge a battery with an emf of 10 V and an internal resistance of 1 Ω.The current in the circuit is:
A battery with EMF 90.0 V has internal resistance Rb = 8.95 Ω . Part A What is the reading Vv of a voltmeter having total resistance Rv = 440 Ω when it is placed across the terminals of the battery? Vv = 88.2 V Part B What is the maximum value that the ratio Rb/Rv may have if the percent error in the reading of the EMF of a battery is not to exceed 5.00 % ? Express your...
An uncharged capacitor and a resistor are connected in series to a source of emf. If e m f = 9.00 V, C = 25.0 µF, and R = 100 Ω, find the following: (a) the time constant of the circuit (s) (b) the maximum charge on the capacitor (µC) (c) the charge on the capacitor after one time constant (µC)
A battery with an emf of 12.00 V has an internal resistance r. When connected to a resistor R, the terminal voltage is 11.70 V and the current is 0.20 A.A) What is the value of the external resistor R?B) What is the internal resistance r of the battery?C) What is the energy dissipated in the battery's internal resistance in 3.7 minutes?D) When a second identical battery is added in series and the external resistor is R = 28 Ohms...
An uncharged capacitor and a resistor are connected in series to a source of emf. If e m f = 6.00 V, C = 18.0 µF, and R = 100 Ω, find the following. (a) the time constant of the circuit ms (b) the maximum charge on the capacitor µC (c) the charge on the capacitor at a time equal to one time constant after the battery is connected µC