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In the activity, click on the K eq and Δ G ∘ quantities to observe how...

In the activity, click on the K eq and Δ G ∘ quantities to observe how they are related. Calculate Δ G ∘ using this relationship and the equilibrium constant ( K eq ) obtained in Part A at T=298K : K eq =1.92× 10 26 Express the Gibbs free energy ( Δ G ∘ ) in joules to three significant figures.

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Answer #1

Answer:

Given,

To determine Delta Go

Temperature T = 298 K

Molar gas constant R = 8.314 J/mol.K

Equilibrium constant Keq = 1.92 x 10^26

Now consider

Standard free energy change

i.e.

Delta Go = -RT ln Keq

= - 8.314 x 298 x ln(1.92 x 10^26)

= -8.314 * 298 * 60.52

Delta Go = -1.50 x 10^5 J

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