ZuoTi.Pro
Question

F. A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of...

F. A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and boiling point of the solution . For the solvent, Kb = 3.08 oC/m and Kf = 3.59 oC/m.
  

G. Butylated hydroxytoluene (BHT) is used as an antioxidant in processed foods. (It prevents fats and oils from becoming rancid.) A solution of 2.500 g of BHT in 100.0 g of benzene had a freezing point of 4.880 oC. What is molecular mass of BHT?. Kf for benzene is 5.065 oC/m

H. In a mountainous location, the boiling point of pure water is found to be 95 oC. How many grams of sodium chloride must be added to 1 kg of water to bring the boiling point back to 100 oC?. Kb for water is 0.512 oC/m. Assume i = 2.


I. What is the boiling point of a solution made by adding 6.69 g of magnesium chloride to 250.0 g of water?. Use the formula of the salt to obtain i. (Kb for water is 0.512 oC/m)

science   chemistry   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
F. A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • The freezing point of water is 0.00°C at 1 atmosphere. A student dissolves 12.54 grams of chromium(II) acetate, Cr(CH3COO)2 (170.1 g/mol), in 158.2 grams of water. Use the table of boiling and freezin...

    The freezing point of water is 0.00°C at 1 atmosphere. A student dissolves 12.54 grams of chromium(II) acetate, Cr(CH3COO)2 (170.1 g/mol), in 158.2 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 The molality of the solution is m. The freezing point of the solution is °C....

  • The boiling point of water is 100.0°C at 1 atmosphere. How many grams of zinc chloride...

    The boiling point of water is 100.0°C at 1 atmosphere. How many grams of zinc chloride (136.3 g/mol), must be dissolved in 209.0 grams of water to raise the boiling point by 0.400°C? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 g zinc chloride.

  • A solution is made by dissolving 0.749 mol of nonelectrolyte solute in 861 g of benzene....

    A solution is made by dissolving 0.749 mol of nonelectrolyte solute in 861 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution. Constants may be found here. Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8 6.59 2.92 80.7 ethanol C2H6O 1.99 –117.3 1.22 78.4 carbon tetrachloride   CCl4 29.8 –22.9 5.03 76.8...

  • A solution is made by dissolving 0.592 mol of nonelectrolyte solute in 767 g of benzene....

    A solution is made by dissolving 0.592 mol of nonelectrolyte solute in 767 g of benzene. Calculate the freezing point, Te, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. T = Colligative Constants Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* Normal freezing Kb value Normal boiling (°C/m) point (°C) (°C/m) point (°C) water H20 1.86 0.00 0.512 100.00 benzene 5.12 5.49 2.53 80.1...

  • The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 12.31 grams...

    The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 12.31 grams of cobalt(II) acetate, Co(CH3COO)2 (177.0 g/mol), in 287.1 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 The molality of the solution is _____m. The boiling point of the solution is  °____C....

  • The boiling point of water is 100.0°C at 1 atmosphere. How many grams of aluminum nitrate...

    The boiling point of water is 100.0°C at 1 atmosphere. How many grams of aluminum nitrate (213.0 g/mol), must be dissolved in 279.0 grams of water to raise the boiling point by 0.450°C? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02

  • A solution is made by dissolving 0.585 mol of nonelectrolyte solute in 877 g of benzene....

    A solution is made by dissolving 0.585 mol of nonelectrolyte solute in 877 g of benzene. Calculate the freezing point, Tf, and boiling point, Tb, of the solution. Constants can be found in the table of colligative constants. Constants for freezing-point depression and boiling-point elevation calculations at 1 atm: Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8...

  • 8. A solution is prepared by dissolving 0.434 moles of ethanol, C2H60, in 150. grams of...

    8. A solution is prepared by dissolving 0.434 moles of ethanol, C2H60, in 150. grams of water. Calculate the molality of the solution, freezing point of the solution, and boiling point of the solution. (Kf of H2O 1.86°C/m; fp of H20 = 0.00°C; Kb of H20 = 0.512°C/m; BP of H20 100.00°C)

  • The boiling point of water is 100.0°C at 1 atmosphere. How many grams of iron(II) iodide...

    The boiling point of water is 100.0°C at 1 atmosphere. How many grams of iron(II) iodide (309.7 g/mol), must be dissolved in 258.0 grams of water to raise the boiling point by 0.300°C? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kb (°C/m) Kf (°C/m) Water H2O 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCl3 3.67 Benzene C6H6 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 ___?___ g iron(II) iodide.

  • 1. A solution was prepared by dissolving 2.20g of urea (H2NCONH2) in 50.00g of water. If...

    1. A solution was prepared by dissolving 2.20g of urea (H2NCONH2) in 50.00g of water. If for H2O Tb = 100C, Tf = 0C, Kb = 0.52C / m and Kf = 1.86C / m, determine the freezing and boiling point of the solution. 2. A solution is prepared by dissolving 17.41g of a substance X in 600g of benzene and the resulting solution is frozen at 4.00C. If the freezing point of pure benzene is 5.55C and its Kf...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT