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NH4Cl(aq) NH3(g) + HCl(aq) G° = 62.3 kJ and H° = 86.4 kJ at 305 K...

NH4Cl(aq) NH3(g) + HCl(aq) G° = 62.3 kJ and H° = 86.4 kJ at 305 K and 1 atm. This reaction is (reactant, product)----- favored under standard conditions at 305 K. The entropy change for the reaction of 2.30 moles of NH4Cl(aq) at this temperature would be ------- J/K.

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