Question

The owner of a local phone store wanted to determine how much customers are willing to...

The owner of a local phone store wanted to determine how much customers are willing to spend on the purchase of a new phone. In a random sample of 13 phones purchased that day, the sample mean was $493.254 and the standard deviation was $21.6007. Calculate a 90% confidence interval to estimate the average price customers are willing to pay per phone. Question 2 options: (If Possible Show on Calculator)

1) ( 482.576 , 503.932 )

2) ( 487.263 , 499.245 )

3) ( 491.472 , 495.036 )

4) ( 482.644 , 503.864 )

5) ( -482.576 , 503.932 )

0 0
Add a comment Improve this question Transcribed image text
Answer #1

a 90% confidence interval to estimate the average price customers are willing to pay per phone

ans-> 1) ( 482.576 , 503.932 )

Add a comment
Know the answer?
Add Answer to:
The owner of a local phone store wanted to determine how much customers are willing to...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza...

    Question 1 (1 point) A customer wants to estimate the average delivery time of a pizza from the local pizza parlor. Over the course of a few months, the customer orders 29 pizzas and records the delivery times. The average delivery time is 23.69 with a standard deviation of 7.212. If the customer estimates the time using a 95% confidence interval, what is the margin of error? Question 1 options: 1) 0.7137 2) 2.2782 3) 2.7433 4) 1.3392 5) 2.739...

  • 1) The owner of a local gas station would like to estimate the mean number of...

    1) The owner of a local gas station would like to estimate the mean number of gallons sold to his customers. Assume that the number of gallons sold follow a normal distribution with a population standard deviation 0f 2.5 gallons. He selects a random sample of 100 sales and finds the mean number of gallons sold equals 9.2 What is the point estimate of the population mean? a. 8.2 b. 2.5 c. 100 d. 9 2) The owner of a...

  • You are hired by Google to research how much people are willing to pay for a...

    You are hired by Google to research how much people are willing to pay for a new cell phone in US. They are especially interested to know if their new phone, Pixel, should be priced similarly to Apple’s iPhone. Google believes that there is a difference between what Android and iPhone users are willing to pay for high-end phones. You are hired to answer this question. To analyze iPhone users your team randomly selects 16 individuals. The sample average for...

  • 1. A random sample of 82 customers, who visited a department store, spent an average of...

    1. A random sample of 82 customers, who visited a department store, spent an average of $71 at this store. Suppose the standard deviation of expenditures at this store is O = $19. What is the e 98% confidence interval for the population mean? 2. A sample of 25 elements produced a mean of 123.4 and a standard deviation of 18.32 Assuming that the population has a normal distribution, what is the 90% confidence interval for the population mean? 3....

  • The owner of a restaurant wants to determine the average number of customers who eat lunch...

    The owner of a restaurant wants to determine the average number of customers who eat lunch at his restaurant each day. A sample of 16 days showed that an average of 130 lunches were served daily. The standard deviation of the sample was 12, Provide a 90% confidence interval estimate for the average number of lunches served per day. If the standard deviation for lifetimes of vacuum cleaners is estimated to be 400 hours, how large a sample must be...

  • 19. The owner of a local convenience store is interested in the average amount spent per...

    19. The owner of a local convenience store is interested in the average amount spent per shopper at a competing convenience store. To find out, she randomly sampled 49 shoppers and asked how much they spent the last time they went to the competing store. The mean expenditure of the 49 customers was $5.82. Assuming the distribution of spending has a Normal distribution with mean μ and standard deviation σ = $1.11, a 92% confidence interval for μ is: ($5.41,...

  • 9. The amount of time that a certain cell phone will keep a charge is known...

    9. The amount of time that a certain cell phone will keep a charge is known to be normally distributed with a standard deviation o= 15 hours. A sample of 45 cell phones has a mean time of 145 hours. Let u represent the population mean time that a cell phone will keep a charge. a. What is the point estimate of u? b. What is the standard error of the point estimate? Round to three decimal places. c. Suppose...

  • 1. In an effort to determine how long phone customers are kept on hold, one airline...

    1. In an effort to determine how long phone customers are kept on hold, one airline took a random sample of 167 phone calls and determined the length of time in minutes each caller was kept on hold. The sample standard deviation was 3.8 minutes. How many more phone customers should be included in the sample to be 99% sure that the sample mean x of hold times is within 3o second of the population mean µ of hold times?...

  • A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for...

    A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1031 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.14 hours with a standard deviation of 0.56 hour. Determine and interpret a 90​% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day.

  • A sociologist conducted a study at a local grocery store to determine how much money shoppers...

    A sociologist conducted a study at a local grocery store to determine how much money shoppers spent on average. She sampled 27 shoppers and calculated the mean amount of money spent to be $95.5 with a standard deviation of $15.39. (5 points) Construct a 95% confidence interval for the mean amount of money spent at the grocery store. (2 points) Three months prior to this study, the manager of the grocery store started an advertising campaign with the goal of...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT