A piston cylinder device with a free floating piston contains 0.3 kg of R-134a at 400 kPa and 0 C. The volume of the cylinder is what?
MOlecular mass of R-134a = 102.3 g / mol
number of moles = W/M = 300/102.3 = 2.93
Using the Universal gas equation we have
PV = nRT
(400000 / 1.01235*10^5) * V = 2.93*0.0821*273
V = 16.63 L
volume of cylinder is 16.63 L
A piston cylinder device with a free floating piston contains 0.3 kg of R-134a at 400...
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