what volume of each solution contains 0.10 mol of KCL ?
part a) 0.206 M KCl
part b) 1.9 M KCl
part c) 0.855 M KCl
To calculate the volume of each solution that contains 0.10 mol of KCl, we can use the formula:
Volume (in liters) = Number of moles / Molarity
Given: Number of moles of KCl = 0.10 mol
Let's calculate the volume for each part:
a) Part a) 0.206 M KCl: Volume = 0.10 mol / 0.206 mol/L ≈ 0.485 L (or 485 mL)
b) Part b) 1.9 M KCl: Volume = 0.10 mol / 1.9 mol/L ≈ 0.0526 L (or 52.6 mL)
c) Part c) 0.855 M KCl: Volume = 0.10 mol / 0.855 mol/L ≈ 0.117 L (or 117 mL)
So, for each part: a) Approximately 0.485 liters (485 mL) of a 0.206 M KCl solution contains 0.10 mol of KCl. b) Approximately 0.0526 liters (52.6 mL) of a 1.9 M KCl solution contains 0.10 mol of KCl. c) Approximately 0.117 liters (117 mL) of a 0.855 M KCl solution contains 0.10 mol of KCl.
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