Be sure to answer all parts. (b) 22.4 g of MgCl2 in the preparation of a 6.6
percent mass solution: |
a) Mass percent = ( mass of urea / mass of solution ) x 100
20.1 / 100 = 7.70 g / mass of solution
0.201 = 7.70 / mass of solution
mass of solution = 7.70 / .201
= 38.31g
Mass of water = mass of solution - mass of urea
= 38.31 - 7.70 = 30.61 g
Mass of water added = 30.61 g
b) Mass percent = ( mass of MgCl2 / mass of solution ) x 100
6.6 = ( 22.4 / mass of solution ) x 100
6.6/100 = 22.4 / mass of solution
.066 = 22.4 / mass of solution
mass of solution = 22.4 / .066
= 339.39 g
mass of water = mass of solution - mass of MgCl2
= 339.39 - 22.4
= 316.99 g
mass of water added = 316.99 g
Be sure to answer all parts. Calculate the amount of water (in grams) that must be...
Calculate the amount of water (in grams) that must be added to each of the following substances to produce the indicated solution 20.7 g of MgCl2 in the preparation of a 6.2% mass solution
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