if 20.0 grams of sodium (na) is reacted with 10.0 grams of water (h20) Wich would be the limiting reactant according to this equation. 2na+2h2o--- 2naoh+h2
Moles of Na = mass / molar mass = 20 / 23 = 0.870 moles
Moles of H2O = mass / molar mass = 10 / 18 = 0.56 moles
From the equation, moles of needed = moles of H2O. Since H2O is in lower quantity, it is the limiting reagent
if 20.0 grams of sodium (na) is reacted with 10.0 grams of water (h20) Wich would...
Sodium metal reacts with water to produce hydrogen gas according to the following equation: 2Na(s) + 2H2O(l)2NaOH(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 20 °C and a pressure of 753 mm Hg. If the wet H2 gas formed occupies a volume of 5.60 L, the number of moles of Na reacted was ____ mol. The vapor pressure of water is 17.5 mm Hg at 20 °C.
5. What is the limiting reactant when 10.0 grams of silver nitrate are reacted with 10.0 g of sodium chloride in water solution according to the following reaction? NaCl (aq) + AgNO3(aq) - NaNO3(aq) + AgCl (s)
For the following reaction, 6.87 grams of water are mixed with excess sodium. The reaction yields 12.6 grams of sodium hydroxide. 2Na(s)+2H2O(l)---->2NaOH(aq)+H2(g) What is the theoretical yield of sodium hydroxide? g What is the percent yield for this reaction? %
Sodium reacts with water according to the reaction: 2Na(s)+2H2O(l)→2NaOH(aq)+H2(g) Identify the oxidizing agent. a) H2O(l) b) NaOH(aq) c) Na(s) d) H2 (g)
10.0 mL of 0.360 M sodium sulfide is reacted with 25.00 mL of 0.415 M silver nitrate according to the chemical equation shown below. (Na2S= 78.05 g/mol, AgNO3= 169.91 g/mol, NaNO3= 85.00 g/mol, Ag2S=172.02 g/mol) Na?2?S (aq) + 2AgNO3? (aq) yields (arrow) 2NaNO?3? (aq) +Ag2S (s) Caculate the theorectical yield of silver sulfde in grams. State which reactant if any any is limiting and explain how you know this. After all the limiting reactant is used, how many moles of...
21. Suppose 30.0 grams of sodium metal and 120.0 grams of oxygen gas are reacted in a closed vessel and the reaction proceeds to completion to produce Na O with no other products. Which reactant is the limiting reagent, and how much of the reagent in excess will be left over?
Collecting Gas over water Sodium metal reacts with water to produce hydrogen gas according to the following equation: 2Na(s) + 2H20(1)—>2NaOH(aq) + H2(g) The product gas, H2, is collected over water at a temperature of 25 °C and a pressure of 746 mm Hg. If the wet H2 gas formed occupies a volume of 7.28 L, the number of grams of H, formed is g. The vapor pressure of water is 23.8 mm Hg at 25 °C.
The reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g) proceeds as follows: 2Na(s) + 2H2O(1)—>2NaOH(aq) + H2(g) When 5.91 g Na(s) reacts with sufficient H2O(1), 47.4 kJ is evolved. Calculate the value of A,H for the chemical equation given. kJ/mol Submit Show Approach Show Tutor Steps
Question 22 of 22 Submit Solid sodium reacts with liquid water to form hydrogen gas according to the equation 2 Na(s) + 2H2O(I) > 2 NaOH(aq) + H2(g) What is the pressure of hydrogen gas in the 20.0 L headspace of a reactor vessel when 1.00 kg sodium is reacted with excess water at 50.0°C? atm 2 3 x 4 6 8 7 +/- 9 0 x 100 Tap here or pull up for additional resources
1. 4.990 grams of C2H4 is reacted with 31.46 gram F2 according to the following equation. How many gram of HF can be formed, assuming 100% yield? C2H4 + 6F2 --> 2CF4 + 4 HF Hint: Find limiting reagent. 6.281 g 8.830 g 4.297 g 17.21 g 20.55 g 18.34 g 11.04 g 25.91 g 2. 49.7 mL of a solution of NaOH is needed to neutralize a solution that contains 1.86 g of H2SO4 in water. What is the molarity...