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if 20.0 grams of sodium (na) is reacted with 10.0 grams of water (h20) Wich would...

if 20.0 grams of sodium (na) is reacted with 10.0 grams of water (h20) Wich would be the limiting reactant according to this equation. 2na+2h2o--- 2naoh+h2

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Answer #1

Moles of Na = mass / molar mass = 20 / 23 = 0.870 moles

Moles of H2O = mass / molar mass = 10 / 18 = 0.56 moles

From the equation, moles of needed = moles of H2O. Since H2O is in lower quantity, it is the limiting reagent

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