Question

In C++ using For Loops;

"Write a program that displays number facts for a number provided by the end user between 1-100 in a table format that includes the number itself, whether the number is a prime number, whether the number is even or odd, whether the number is a perfect square and all of its factors. "

It should also print this information.

Answer 1

c++ Code:

#include<iostream>

#include<math.h>

using namespace std;

bool isPrime(int num){

bool flag=true;

for(int i = 2; i <= num / 2; i++) {

if(num % i == 0) {

flag = false;

break;

}

}

return flag;

}

bool isPerfectSquare(long double n)

{

long double sqr = sqrt(n);

return ((sqr - floor(sqr)) == 0);

}

int main(){

int n;

cout<<"Enter a number between 1-100: ";

do{

cin>>n;

}while(n<1 || n>100);

cout<<"Number entered: "<<n<<endl;

bool flag=isPrime(n);

if(flag==true)

cout<<n<<" is a prime number"<<endl;

else

cout<<n<<" is not a prime number"<<endl;

if(n%2==0)

cout<<n<<" is not odd number"<<endl;

else

cout<<n<<" is an odd number"<<endl;

if(isPerfectSquare(n))

cout<<n<<" is a perfect square"<<endl;

else

cout<<n<<" is not a perfect square"<<endl;

cout<<"Factors of "<<n<<" are: ";

for(int i=1;i<=n;i++){

if(n%i==0)

cout<<i<<" ";

}

}

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