A soft drink machine outputs a mean of 23 ounces per cup. The machine's output is normally distributed with a standard deviation of 4 ounces. What is the probability of filling a cup between 27 and 31 ounces? Round your answer to four decimal places.
Solution :
Given that ,
P(27 < x < 31) = P[(27 - 23)/ 4) < (x - ) / < (31 - 23) / 4) ]
= P(1 < z < 2)
= P(z < 2) - P(z < 1)
= 0.9772 - 0.8413
= 0.1359
Probability = 0.1359
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