When species combine to produce a coordination complex, the equilibrium constant for the reaction is called is the formation constant, Kf.
For example, the iron(II) ion, Fe2+, can combine with the cyanide ion, CN−, to form the complex [Fe(CN)6]4− according to the equation
Fe2+(aq)+6CN−(aq)⇌[Fe(CN)6]4−(aq)
where Kf=4.21×1045.
This reaction is what makes cyanide so toxic to human beings and other animals. The cyanide ion binds to the iron that red blood cells use to carry oxygen around the body, thus interfering with the blood's ability to deliver oxygen to the tissues. It is this toxicity that has made the use of cyanide in gold mining controversial. Most states now ban the use of cyanide in leaching gold out of low-grade ore.
The average human body contains 5.10 L of blood with a Fe2+ concentration of 1.50×10−5 M . If a person ingests 6.00 mL of 24.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
When species combine to produce a coordination complex, the equilibrium constant for the reaction is called...
Part A When species combine to produce a coordination complex, the equilibrium constant for the reaction is called is the formation constant, K. For example, the iron(W) lon, Fe2+, can combine with the cyanide lon, CN, to form the complex Fe(CN)/ according to the equation Fe+ (aq) + 6CN- (aq) - [Fe(CN) (aq) where K 4.21 x 104 This reaction is what makes cyanide so toxic to human beings and other animals. The cyanide lon binds to the Iron that...
i need help plz Cyanide Poloning Review Constants Periodic Table - Part A When species combine to produce a coordination complex, the brum constant for the reaction is called is the formation constant For example, the iron 10 ton. Pe can combine with the cyanide lon, ON to form the complex Fe(CN):) according to the lion Peep) +6CN (2) Fe(CN)x]*- (aq) where K 4.21 x 10" This reactions what makes ceride so low to human beings and other was. The...
The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.40×10−5M . If a person ingests 5.00 mL of 23.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 6.40 L of blood with a Fe2+ concentration of 1.80×10−5 M . If a person ingests 8.00 mL of 12.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 6.40 L of blood with a Fe2+ concentration of 3.10×10−5 M . If a person ingests 5.00 mL of 12.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 5.00 L of blood with a Fe2+ concentration of 1.60×10−5 M . If a person ingests 9.00 mL of 12.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.90×10−5 M . If a person ingests 9.00 mL of 11.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically.
The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.20×10−5 M . If a person ingests 10.0 mL of 17.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically.
The average human body contains 5.50 L of blood with a Fe2+ concentration of 2.10×10−5mol L−1. If a person ingests 5.00 mL of 22.0 mmol L−1 NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?
The average human body contains 5.10 L of blood with a Fe2+ concentration of 2.60×10−5mol L−1. If a person ingests 12.0 mL of 18.0 mol L−1 NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically.