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A galvanic cell is prepared using the following half-cells: (i) MnO4-(0.283M), Mn2+(0.081M), and H+(1.0 M), and...

A galvanic cell is prepared using the following half-cells:

(i) MnO4-(0.283M), Mn2+(0.081M), and H+(1.0 M), and (ii) Sn2+(0.236M) and Sn4+(0.145M).

MnO4-+ 8H++ 5e-↔Mn2++ 4H2O Eo= 1.507 V

Sn4++ 2e-↔Sn2+Eo= 0.151 V

a)Calculate the galvanic cell voltage.

b)Write the complete cell description.

c)Write the cell reaction indicating clearly the direction of spontaneous reaction.

d)Name the electrode (anode or cathode), give the polarity (positive or negative) of the electrode, and state the reaction (oxidation or reduction) occurring in the tin half-cell.

Please provide complete solutions to ALL parts thanks!!

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