You have a simple circuit with a total resistance of 5 Ω. If a 3 -A current is maintained in that circuit, how much energy (in Joule) is delivered through the circuit in twenty five seconds?
(1125J IS NOT CORRECT ANSWER)
Energy= Power*Time
Power=I^2*R
Power= 3^2*5
Power= 45 watt
Energy= 45*5
Energy= 225 Joule
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