A solution prepared by mixing
100 mL of 0.10 M NaOH
140 mL of 0.10 M HCl
100 mL of 0.10 M NH3
has a pH of:
Kb (NH3) = 1.8 x 10-5
9.08
4.57
7.00
4.92
9.43
since HCl and NaOH is strong acid and base so completely neutralize.
some amount of HCl left unreacted that react with NH3
then to draw ICE table.
then using ka to find the pH.
A solution prepared by mixing 100 mL of 0.10 M NaOH 140 mL of 0.10 M...
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