Question

In the carnival game​ Under-or-Over-Seven, a pair of fair dice is rolled​ once, and the resulting...

In the carnival game​ Under-or-Over-Seven, a pair of fair dice is rolled​ once, and the resulting sum determines whether the player wins or loses his or her bet. For​ example, using method​ one, the player can bet $2.00 that the sum will be under​ 7, that​ is, 2,​ 3, 4,​ 5, or 6. For this​ bet, the player wins ​$2.00 if the result is under 7 and loses ​$2.00 if the outcome equals or is greater than 7.​ Similarly, using method​ two, the player can bet ​$2.00 that the sum will be over​ 7, that​ is, 8,​ 9, 10,​ 11, or 12.​ Here, the player wins $2.00 if the result is over 7 but loses ​$2.00 if the result is 7 or under. A third method of play is to bet ​$2.00 on the outcome 7. For this​ bet, the player wins ​$8.00 if the result of the roll is 7 and loses ​$2.00 otherwise. Complete parts​ (a) through​ (d).

Outcomes of a two dice roll

1

2

3

4

5

6

1

2

3

4

5

6

7

2

3

4

5

6

7

8

3

4

5

6

7

8

9

4

5

6

7

8

9

10

5

6

7

8

9

10

11

6

7

8

9

10

11

12

a. Construct the probability distribution representing the different outcomes that are possible for a ​$1.00 bet using method one.

X

​P(X)

  

​ $

type a fraction

−$

fraction

​(Type an exact answer in simplified​ form.)

b. Construct the probability distribution representing the different outcomes that are possible for a ​$1.00 bet using method two.

X

​P(X)

  

​ $

fraction

−​$

fraction

​(Type an exact answer in simplified​ form.)

c. Construct the probability distribution representing the different outcomes that are possible for a ​$1.00 bet using method three.

X

​P(X)

​$

−​$

d. What is the expected​ long-run profit​ (or loss) to the player for each of the three methods of​ play?

Method one expected profit​ (or loss)

muμ

=

​$

Method two expected profit​ (or loss)

muμ

=

​$

Method three expected profit​ (or loss)

muμ

=

​$

​$​(Round to the nearest cent as​ needed.)

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