A pet owner told the vet that he would drop his pet off between the hours...
A pet owner told the vet that he would drop his pet off between the hours of 9:30 AM and 1:45 PM. The vet plans to take lunch from 11:15 AM to 12:00 PM.
a. What is the probability that the owner will come during his lunch?
Round to 3 significant digits
b. When should he expect the owner to arrive?
: :
(click to select)AMPM
Homework Answers
This is a uniform distribution which ranges between 0 minute and 195 minutes. Hence,
a) P(Owner will come between 11:15 AM and 12:00 PM)
= 15 / (195 - 0)
= 15/195
= 0.077
b) Expected value = (0 + 195)/2 = 97.5
Hence,
Owner is expected to arrive 97.5 minutes after 9:30 i.e. 11 : 08 AM
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