A Turing machine M decides a language L is M:
Group of answer choices
All of these apply.
Accepts all strings in L and M rejects all strings not in L.
Accepts some strings in L and M rejects some strings not in L.
Accepts all strings in L that are recognizable.
A Turing machine M decides a language L is M: Group of answer choices All of...
Help me answer this question plz! 4. Let L = { (A) M is a Turing machine that accepts more than one string } a) Define the notions of Turing-recognisable language and undecidable language. b) Is L Turing-recognisable? Justify your answer with an informal argument. c) Justify with a formal proof your answer to b) d) Prove that L is undecidable. (Hint: use Rice's theorem.) e) Modify your answer to b) when instead of L you have the language Ln...
2. Let L = {hMi: M is a Turing machine that accepts at least two binary strings}. a) Define the notions of a recognisable language and an undecidable language. [5 marks] b) Is L Turing-recognisable? Justify your answer with an informal argument. [5 marks] c) Prove that L is undecidable. (Hint: use Rice’s theorem.) [20 marks] d) Bonus: Justify with a formal proof your answer to b). [20 marks] 2. Let L-M M): M is a Turing machine that accepts...
2. Let L-M M): M is a Turing machine that accepts at least two binary strings. a) Define the notions of a recognisable language and an undecidable language. [5 marks [5 marks] b) Is L Turing-recognisable? Justify your answer with an informal argument. c) Prove that L is undecidable. (Hint: use Rice's theorem.) [20 marks] 20 marks] d) Bonus: Justify with a formal proof your answer to b). 2. Let L-M M): M is a Turing machine that accepts at...
please answer and I will rate! 3. Let L = {M M is a Turing machine and L(M) is empty), where L(M) is the language accepted by M. Prove Lis undecidable by finding a reduction from Arm to it, where Ayv-<<MwM is a Turing machine and M accepts w). Answer:
Describe a Turing machine that decides L5 = {0^3^n |n ∈ N} – the language consisting of all strings of zeroes whose length is a power of 3.
Show that the language A = {<M1> | the language accepted by the Turing Machine M1 is 1*} is not decidable. Present your proof in the style of the proof of Th. 5.3, which shows below. PROOF We let R be a TM that decides REGULARTm and construct TM S to decide ATM. Then S works in the following manner. S - "On input (M, w), where M is a TM and w is a string: 1. Construct the following...
3. Let L= {MM is a Turing machine and L(M) is empty), where L(M) is the language accepted by M. Prove L is undecidable by finding a reduction from Arm to it, where Arm={<M,w>| M is a Turing machine and M accepts w}
Consider the language LOOPS = {<M,w> | M is a Turing machine and M loops forever on input w} Is LOOPS Turing decidable? Explain why or why not. Is LOOPS Turing recognizable? Explain why or why not.
please answer a,b, and c Consider the following Turing Machine. M = “On input hA,Bi where A and B are DFAs: 1. Iterate through strings in Σ∗ in shortlex order; where Σ represents the common symbols of their input alphabets. For each string iterated, simulate both A and B on it. 2. If a string is ever encountered that both A and B accept, then accept.” (a) (2 points) Give a description, in English, of the language that M recognizes....
19. (1 point) Suppose that L is undecidable and L is recognizable. Which of the following could be false? A. I is co-Turing recognizable. B. I is not recognizable. C. I is undecidable. D. L* is not recognizable. E. None of the above. 20. (2 points) Let ETM {(M)|L(M) = 0} and EQTM = {(M1, M2)|L(Mi) = L(M2)}. We want to show that EQTM is undecidable by reducing Etm to EQTM and we do this by assuming R is a...