Question

Iron (III) oxide reacts with carbon monoxide to produce iron and carbon dioxide. Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

Part A What is the percent yield of iron if the reaction of 67.0 g of iron(III) oxide produces 14.3 g of iron?

Answer 1

The given balanced reaction is

Hence, 1 mol of Fe₂O₃ produces two moles of Fe theoretically.

Now, amount of Fe₂O₃ taken is 67.0 g

Molar mass of Fe₂O₃ = 159.69 g/mol

Hence, number of moles of Fe₂O₃ taken is

Hence, theoretical number of moles of Fe produced will be

Atomic mass of Fe = 55.845 g/mol

Hence, theoretical yield of Fe can be calculated as follows

Now, the actual yield of Fe is given to be 14.3 g

Hence, the percent yield can be calculated as follows:

Hence, the percent yield of Fe is about 30.5 %. (Rounded to three significant figures).