Let S1 = { 1, 2, 3 }, S2 = { a, b }, S3 =...

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Let S1 = { 1, 2, 3 }, S2 = { a, b }, S3 =...

Let S₁ = { 1, 2, 3 }, S₂ = { a, b }, S₃ = { 4, 5, 6 }. Show a B-tree of minimum degree t = 3 that contains the 18 tuple keys in S₁ × S₂ × S₃, ordered by the linear order defined in (a). Assume that a <₂ b in S₂.

please show the 18 tuple at first which is a cartesian product of s1,s2 and s3 and insert them into a B tree whose minimum degree is 3 . please dont copy paste from previous number.

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Answer 1

Answer #1

The cartesian product will be : S1 X S2 X S3 = { (1,a,4) (1,b,4) (2,a,4) (2,b,4) (3, a,4) (3,b,4) (1,a,5) (1,b,5) (2,a,5) (2,b,5) (3,a,5) (3,b,5) (1,a,6) (1,b,6) (2,a,6)(2,b,6) (3,a,6)(3,b,6)}

The required B-tree is as follows: (Assuming a<b in S2)

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Answer 2

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