Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places.
Of 89 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance.
proportion p = 66/89
standard error = sqrt( p *(1-p)/n)
margin of error = z-score * standard error
= 1.645 * sqrt( (66/89) * (23/89)/89)
= 0.07633
lower limit = (66/89) - 0.07633 = 0.6652
upper limit = (66/89) + 0.07633 = 0.8179
Use the given degree of confidence and sample data to construct a confidence interval for the...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal palces. or 97 adults selected randomly from one town, B4 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance O A. 0.581 <p <0.739 OB. 0.566 <p <0.754 OC. 0.536 <p<0.784 OD. 0.548<p<0.772
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. 24) Of 80 adults selected randomly from one town, 64 have health insurance. Find a 90% confidence 24) interval for the true proportion of all adults in the town who have health insurance. A) 0.696 < p0.904 C) 0.712 <p0.888 B) 0.685 <p<0.915 D) 0.726< p<0.874 25) Of 382 randomly selected medical students, 27 said that they planned to work in...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal palces Of 98 adults selected random from one town, 68 have health insurance Find a 90% confidence interval adults in he own who have heal e proportion on r e a ns rance 0585 < p < 0 802 B. 0.617<p<0.770 A. C. 0603 p<0.785 D. 0.574p<0.814 Use the given degree of confidence and sample data to...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places of 107 randomly selected adults, 34 were found to have high blood pressure. Construct a 95% confidence interval for the true percentage of all adults that have high blood pressure O A. 22.953% <p < 40.598% OB. 21.288% <p<42.263% OC. 20.163% <p < 43.389% D. 24.349% <p <39.203%
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places. Of 145 randomly selected adults, 30 were found to have high blood pressure. Construct a 95% confidence interval for the true percentage of all adults that have high blood pressure. A.15.139%<p<26.240% B.14.096%<p<27.283% C.12.011%<p<29.369% D.12.852%<p<28.528%
1. Use the given degree of confidence and sample data to construct a confidence interval for the point) population proportion p. A survey of 865 voters in one state reveals that 408 favor approval of an issue before the legislature. Construct the 95% confidence interval for the true proportion of all voters in the state who favor approval. 0 0.438<p0.505 0 0.444 p0.500 0 0.435<p<0.508 O 0.471 p0.472 2. Use the given data to find the minimum sample size required...
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places When 310 college students are randomly selected and surveyed, it is found that 112 own a car. Find a 99% confidence interval for the true proportion of all college students who own a car. O A. 0.291 <p<0.432 OB. 0.298 <p<0.425 OC. 0.316<p<0.406 OD. 0.308<p <0.415
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Round to three decimal places. When 263 college students are randomly selected and su ve ed, it is found that 121 own a car. Find a 99% confidence interval for the true proportion of all college students who own a car O A. 0.410 sp<0.511 OB, 0.388 <p<0532 O C. 0.381p<0.539 OD. 0.400<p<0520
Use the given degree of confidence and sample data to construct a confidence interval for the population mean y Assume that the population has a normal distribution Thirty randomly selected students took the calculus final the sample mean was 90 and the standard deviation was 5.1. construct a 90% confidence interval for the mean score of all students. Round to be decimal places O A 87.44 <<92.56 OB. 87.71 <<92.29 OC 8743<<92.57 OD 8842 <<91.58
Use the given degree of confidence and sample data to construct a confidence interval for the population proportion 7) A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate.