A tuna fish can (4.0 cm radius) rolls at 2.5 m/s on a level surface and encounters a 45'' incline. How far up the incline does it roll?
Usinh conservation of energy
Potential energy possessed = rotational KE + translational kE
mg h = 0.5 I w^2 + 0.5 m v^2
m *9.8* (d sin 45) = 0.5* (0.5 m r^2) ( v/r)^2 + 0.5 m v^2
9.8* d sin 45 = 0.25 * 2.5^2 + 0.5* 2.5^2
d = 0.676 m
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