Red | Orange | Yellow | Green | Purple | Total |
1046. | 1066 | 977 | 1029 | 969 | 5087 |
Suppose you are going to randomly select two Skittles from the bag YOU purchased.
*show your work
Part a
When first is purple probability is 969/5087
And when you replace it and again choose then having a purple is same as 969/5087
So probability is (969/5087)(969/5087)
= 0.03628
part b)
When first is purple and without replacement 1 is already taken so left with 5086 left and out of 969 purples 968 left..
So (969/5087)(968/5086) = 0.03625
Part c)
First is purple i.e. 969/5087
And after replacing non purples are 4118 out of 5087
So probability is (969/5087)(4118/5087)
= 0.154200
Part D)
Probability that at least one is purple...
So it is equal to 1- probability of no purple
i.e. 1-(4118/5087)
= 0.190485
Red Orange Yellow Green Purple Total 1046. 1066 977 1029 969 5087 Suppose you are...
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