Calculate the theoretical pH of a solution when started with 10 mL of .2 M acetic acid and is diluted to 50 mL with distilled water.
concentration of acetic acid = 10 x 0.2 / 50
= 0.04 M
Ka of acetic acid = 1.8 x 10^-5
[H+] = sqrt (Ka x C)
= sqrt (1.8 x 10^-5 x 0.04)
= 8.48 x 10^-4 M
pH = -log [H+] = -log (8.48 x 10^-4)
pH = 3.07
Calculate the theoretical pH of a solution when started with 10 mL of .2 M acetic...
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The Ka value for acetic acid, CH3COOH(aq) , is 1.8×10-5 M . Calculate the pH of a 2.80 M acetic acid solution.Calculate the pH of the resulting solution when 2.50 mL of the 2.80 M acetic acid is diluted to make a 250.0 mL solution.
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