The average cost of six month Georgia auto insurance in 2018 was $900. Assume the standard deviation is σ = $150. What will be the probability of a value within $100 of the population mean?
68.26%
95.44%
78.88%
49.08%
The average cost of six month Georgia auto insurance in 2018 was $900. Assume the standard...
The average cost of six month Georgia auto insurance in 2018 was $880. Assume the standard deviation is σ = $80. When determining the probability of a value within $100 of the population mean, what would be the representation of the problem in statistical terms? P (600 < x < 800) P (780 < x < 980) P (800 < x < 1,000) P (850 < x < 1,050)
Suppose that the average annual cost of automobile insurance is $850 with an estimated population standard deviation of $245 a.)What is the probability that a simple random sample of size 150 insured automobiles will have a sample mean insurance cost greater than $950? b.)What is the probability that a simple random sample of size 50 insured automobile will have a sample mean insurance cost within $25 of the population mean?
CNNBC recently reported that the mean annual cost of auto insurance is 1009 dollars. Assume the standard deviation is 223 dollars. You take a simple random sample of 100 auto insurance policies. Find the probability that a single randomly selected value is less than 983 dollars. P(X < 983) = Find the probability that a sample of size n=100n=100 is randomly selected with a mean less than 983 dollars. P(¯xx¯ < 983) = Enter your answers as numbers accurate to...
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CNNBC recently reported that the mean annual cost of auto insurance is 996 dollars. Assume the standard deviation is 189 dollars. You will use a simple random sample of 90 auto insurance policies. Find the probability that a random sample of size n=90 has a mean value between 998 and 1045.8 dollars. P(998 < M < 1045.8) =
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CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 277 dollars. You take a simple random sample of 87 auto insurance policies. Find the probability that a single randomly selected value exceeds 970 dollars. P(X > 970) = __________ Find the probability that a sample of size n=87 is randomly selected with a mean that exceeds 970 dollars. P(M > 970) = ________ Enter your answers as numbers accurate to...
CNNBC recently reported that the mean annual cost of auto insurance is 1042 dollars. Assume the standard deviation is 159 dollars. You will use a simple random sample of 61 auto insurance policies. Find the probability that a single randomly selected policy has a mean value between 1031.8 and 1097 dollars. P(1031.8 < X < 1097) - Find the probability that a random sample of size n = 61 has a mean value between 1031.8 and 1097 dollars. P(1031.8 <...