Suppose that all of the outcomes of a random variable are left curly bracket a comma space b comma space c comma space d right curly bracket, and that each outcome as an equal bevelled 1 fourth probability of occurring. Define the events A equals left curly bracket a comma b comma c right curly bracket, B equals left curly bracket c comma d right curly bracket, C equals left curly bracket d right curly bracket, and D={b,c}. True or false: The events B and D are independent.
True
False
P(B) = 2/4 = 1/2
P(D) = 2/4 = 1/2
There is one element common in B and D i.e. b. So,
P(B and D) = 1/4
P(B)P(D) = (1/2)*(1/2) = 1/4
Since P(B and D) = P(B)P(D)
B and D are independent.
The statement is True.
Suppose that all of the outcomes of a random variable are left curly bracket a comma...
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