Water’s specific heat equal to 4190 J/kg·K, how much work one needs to do to increase the temperature of 0.5 kg of water by 1oC?
A. 0 J
B. 2,095 J
C. 4,190 J
D. 574,344 J
here,
the specific heat of water , C = 4190 J/kgK
mass of water , m = 0.5 kg
change in temperature , dT = 1 degree C
the work done required , W = m * C * dT
W = 0.5 * 4190 * 1 J
W = 2095 J
the work done required is B) 2095 J
Water’s specific heat equal to 4190 J/kg·K, how much work one needs to do to increase...
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