How is it when n goes to infinity,
T(n) = 4n*(1 - nlog4(3/4)) + nlog4(3)
becomes Big-Oh,
T(n) = O(n)
?
`Hey,
Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.
Let f(n)=4n*(1 - nlog4(3/4)) + nlog4(3)
g(n)=n
So, f(n)/g(n)=(4*n*(1 - nlog4(3/4))+nlog4(3))/n
=4*(1 - nlog4(3/4))+nlog4(3)-1
So,
for n tending inf
nlog4(3)-1 goes 0
4*(1 - nlog4(3/4)) goes inf
So,
f/g tends inf
Kindly revert for any queries
Thanks.
How is it when n goes to infinity, T(n) = 4n*(1 - nlog4(3/4)) + nlog4(3) becomes...
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