Question

What is the molecular formula of each compound? (Type your answer using the format C6H12O6 for...

What is the molecular formula of each compound? (Type your answer using the format C6H12O6 for C6H12O6 and use the same order of the elements as in the empirical formulas.) (a) empirical formula C3H6O2 ( = 74.08 g/mol) (b) empirical formula HgCl ( = 472.1 g/mol) (c) empirical formula NO2 ( = 92.02 g/mol) (d) empirical formula CHCl ( = 96.94 g/mol)

0 0
Add a comment Improve this question Transcribed image text
Answer #1

a) empirical formula C3H6O2 ( = 74.08 g/mol)

empirical formula mass = 3 x 12 + 6 x 1 + 2 x 16 = 74

n = 74.08 / 74 = 1

molecular formula = n x empirical formula

                              = 1 x C3H6O2

                             = C3H6O2

molecular formula = C3H6O2

(b) empirical formula HgCl ( = 472.1 g/mol)

HgCl mass = 200.59 + 35.5 = 236.09

n = 472.1 / 236.09 = 2

molecular formula = 2 x HgCl

                               = Hg2Cl2

molecular formula = Hg2Cl2

    (c) empirical formula NO2 ( = 92.02 g/mol)

molecular formula =N2O4

(d) empirical formula CHCl ( = 96.94 g/mol)

CHCl = 12 + 1 + 35.5 = 48.5

n = 2

molecular formula = C2H2Cl2

Add a comment
Know the answer?
Add Answer to:
What is the molecular formula of each compound? (Type your answer using the format C6H12O6 for...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Type your answer In the box The molecular formula of a compound having an empirical formula...

    Type your answer In the box The molecular formula of a compound having an empirical formula NH2。(-32.05 g/mol) is N Do you know the answer? Unsure No iden I know it Think so

  • Section 114 Empirical and Molecular Formula:s In your textbook, resd obout percent Answer the folloving qpestions....

    Section 114 Empirical and Molecular Formula:s In your textbook, resd obout percent Answer the folloving qpestions. z. Deseribe how to find tdue percent composition of a compound if you know the tmass of a semple of a compound nnd the mass of each element in the sample In your textbook, read about emplrical and molecular Circle the tetter of the choice thát best answers the question. formulas 3. Which information about a cormpound can you use to begin to d...

  • A 11.76 gram sample of an organic compound containing only C, H, and O is analyzed...

    A 11.76 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 20.95 g CO2 and 8.579 g H2O are produced. In a separate experiment, the molar mass is found to be 74.08 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formula = molecular formula =

  • 11 WIBUS. 19. Percent composition problems (Empirical formula and Molecular formula) A. Fructose, C6H12O6, is a...

    11 WIBUS. 19. Percent composition problems (Empirical formula and Molecular formula) A. Fructose, C6H12O6, is a sugar commonly derived from corn and is 1.73 times as sweet as sucrose. Calculate the percent composition of carbon, hydrogen and oxygen in fructose. B. An unknown compound is found in tree sap. It has been shown to be composed of 40.0% carbon, 6.7% hydrogen and 53.3% oxygen by mass. It was also discovered the 5.00 moles of the material has a mass of...

  • 3. Write the empirical formula for each of the following molecular formulas. C6H12O6 C2H204 C2H4O2 C4H8O2

    3. Write the empirical formula for each of the following molecular formulas. C6H12O6 C2H204 C2H4O2 C4H8O2

  • If the substance has a molecular mass of 160 +/- 5 g/mol, what is its molecular formula?

    (a) The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. Combustion of 7.23 mg of ethyl butyrate produces16.43 mg of CO2 and 6.71 mg of H2O. What is the empirical formula of the compound? (Type your answer using the format CO2 for CO2.)(b) Nicotine, a component of tobacco, is composed of C, H, and N. A 4.725 mg sample of nicotine was combusted, producing 12.818 mg of CO2 and 3.675 mg of...

  • Determined the Empirical formula and molecular formula for the following? A 11.81 gram sample of an...

    Determined the Empirical formula and molecular formula for the following? A 11.81 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 14.98 grams of CO2 and 4.089 grams of H2O are produced. In a separate experiment, the molar mass is found to be 104.1 g/mol. Determine the empirical formula and the molecular formula of the organic compound. Enter the elements in the order C, H, O empirical formula = molecular formula =

  • A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields...

    A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields 15.48 mg CO2 and 7.39 mg H20. The molar mass of the compound is 182.2 g/mol What are the empirical and molecular formulas of the compound? (Enter the elements in the order: C, H, O) The empirical formula: The molecular formula

  • A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields...

    A compound contains only carbon, hydrogen, and oxygen. Combustion of 10.68 mg of the compound yields 15.48 mg CO2 and 7.39 mg H2O. The molar mass of the compound is 182.2 g/mol. What are the empirical and molecular formulas of the compound? (Enter the elements in the order: C, H, O.) The empirical formula:? The molecular formula:?

  • please answer all the question

    1. When 4.912 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 15.41 grams of CO2 and 6.311 grams of H2O were produced.In a separate experiment, the molar mass of the compound was found to be 28.05 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon.Enter the elements in the order presented in the question.empirical formula =molecular formula =2. When 6.848 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.49 grams of CO2 and 8.799 grams of H2O were produced.In a separate experiment, the molar mass...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT