Balance these redox equations in basic solution.
CrO4-2+
S2O4-2 -> Cr(OH)3 +
SO3-2
this equation balanced based on oxidation half reaction and reduction half reaction in basic medium
Balance these redox equations in basic solution. CrO4-2+ S2O4-2 -> Cr(OH)3 + SO3-2
Balance the following Redox Equations in Basic Mediums. Redox Reactions in Basic Solution 1. Al(s) + MnO4¯ (aq) ¾® MnO2(s) + Al(OH)4¯ (aq) 2. NO2¯ (aq) + Al(s) ¾® NH3(aq) + AlO2¯ (aq) 3. Cr(s) + CrO42-(aq) ¾® Cr(OH)3(s) Note: Cr(OH)3 is found in BOTH half reactions! 4. Cl2(aq) + Br2(l) ¾® OBr¯ (aq) + Cl¯ (aq) 5. S8(aq) + MnO4¯ (aq) ¾® SO42-(aq) + MnO2(s)
Balance the following redox equations: CrO_4^2- + Fe^2+ rightarrow Cr^3+ + Fe^3+ (in acidic solution) MnO^4^- + CIO_2^- rightarrow MnO^2 + CIO_4^- (in basic solution)
Balance the following redox reaction in basic solution. Cl (aq)+Cro (aq) - Cl2(g)+Cr(OH)3(s) Cl (aq) Cro (aq) C,(g) Cr(OH), (s)
BALANCE the redox equation in a BASIC solution and FIND the oxidizing and reducing agents: CrI3(s) + H2O2(aq) = CrO4^2-(aq) + IO4-(aq) The equation is in an acidic solition
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): VŽ+ + V(OH). - VO2 (b) (acid solution): C 02 + MnO - CO2(g) + Mn (c) (basic solution): Cr(OH), (s) + H2O2 → CrO
[References) Balance the following redox reaction, which takes place in basic solution. Fe(OH),(s) + Cr(s) + Fe(OH),(s) + Cr(OH),(6) (Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.) Fe(OH),(s) + Cr(s) + Fe(OH),(s) + Cr(OH),(s) + Submit Answer Try Another Version 10 item attempts remaining
3. Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): Cr0(aq) + U" (aq) → Cr" (aq) +UO; (aq) (b) (acid solution): Cr(s) + O2(g) → Cr* (aq) (C) (basic solution): P. (s) + OH' (aq) → PH; (g) + H2PO2 (aq)
Balance the following redox reaction equation first in acidic solution and then in a basic solution: Cr (s) + MnO2 (s) --> Mn+2 (aq) + Cr+3 (aq)
Balance the following basic Redox reaction: Cr3+ (aq) + MnO2 (s) ----------> Mn2+ (aq) + CrO4 2- (aq)
Balance the following redox equations by the ion-electron half-reaction method: (a) (acid solution): MnO2 (s) + Cl → Mn2+ + Cl2 (g) (b) (acid solution): NaBiO; (s) + Ce3+ BiO+ + Ce4+ + Na+ (c) (basic solution): Fe(OH)2 (s) + CrO42- → Fe,0, (s) + Cr(OH)4